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Lina20 [59]
3 years ago
6

True or False: The more mass an object has, the faster it will fall.

Physics
2 answers:
Elza [17]3 years ago
8 0

Answer:

True

Explanation:

solong [7]3 years ago
6 0

Answer:yes yes yes yes YES!

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The temperature at a point (x, y) on a flat metal plate is given by T(x, y) = 45/(6 + x2 + y2), where T is measured in °C and x,
Taya2010 [7]

Answer:

Change in x direction is -1.054^{o}C

Change in y direction is -0.35^{o}C

Explanation:

The temperature is given by we need to find gradient of temperature to obtain the rate of change thus

T(x,y)=\frac{45}{6+x^{2}+y^{2}}\\\\\therefore \bigtriangledown T(x,y)=\frac{\partial T(x,y)}{\partial x} \widehat{i}+\frac{\partial T(x,y)}{\partial y} \widehat{j}\\\\\frac{\partial T(x,y)}{\partial x}=\frac{-45}{(6+x^{2}+y^{2})^{2}}\times 2x\widehat{i}\\\\\frac{\partial T(x,y)}{\partial y}=\frac{-45}{(6+x^{2}+y^{2})^{2}}\times 2y\widehat{j}\\\\

Now the rate of change at (3,1) in

1) X direction is given by

\frac{\partial T(3,1)}{\partial x}=\frac{-45}{(6+3^{2}+1^{2})^{2}}\times 2\times 3\widehat{i}=-1.054\widehat{i}

2) Y direction is given by

\frac{\partial T(3,1)}{\partial y}=\frac{-45}{(6+3^{2}+1^{2})^{2}}\times 2\times 1\widehat{j}=-0.35\widehat{j}\\\\

3 0
3 years ago
Question must be solved using only symbolic algebra.During the experiment if you could triple the breakaway magnetic force with
Papessa [141]

Answer:

An attachment has been added

Explanation:

3 0
3 years ago
A ball is thrown straight up from the ground with speed v0. At the same instant, a second ball is dropped from rest from a heigh
dlinn [17]

Answer:

a) t = H/v0

b) H = -(v0)²/g

Explanation:

Hi there!

a)The position of the balls can be calculated using the following equation:

y = y0 + v0 · t + 1/2 · g · t²

Where:

y = height of the ball at time t.

y0 = initial height.

v0 = initial velocity.

g = acceleration due to gravity.

t = time.

For the ball that is thrown upwards, the initial height is zero, then, the equation can be written as follows:

y = v0 · t + 1/2 · g · t²

The second ball is initially at a height H and the initial velocity is zero. The equation of height for the second ball will be:

y = H + 1/2 · g · t²

When the two balls collide, their height is the same. Then, equalizing both equations we can obtain the time at which they collide:

v0 · t + 1/2 · g · t² = H + 1/2 · g · t²

v0 · t = H

t = H/v0

b) When the first ball is at the highest point its velocity is zero. Using the equation of velocity we can find the time at which the ball is at that point. The equation of velocity is the following:

v = v0 + g · t

At the highest point v = 0.

0 = v0 + g · t

Solving for t:

-v0/g = t

The time at which the first ball is at the highest point is t = -v0/g

The time at which both balls collide was calculated above:

t = H/v0

Then, equalizing both times and solving for H:

H/v0 = -v0/g

H = -v0/g · v0

H = -(v0)²/g

3 0
3 years ago
A stone dropped from the top of a 80m high building strikes the ground at 40 m/s after falling for 4 seconds. The stone's potent
Sergeu [11.5K]

Answer: c. 40m

Explanation:

See picture

3 0
3 years ago
Water flows over a section of Niagara Falls at the rate of 1.2×106 kg/s and falls 50.0 m. How much power is generated by the fal
quester [9]

Answer:

5.88×10⁸ W

Explanation:

Power = energy / time

P = mgh / t

P = (m/t) gh

P = (1.2×10⁶ kg/s) (9.8 m/s²) (50.0 m)

P = 5.88×10⁸ W

7 0
2 years ago
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