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stealth61 [152]
3 years ago
8

A car is traveling at 65 mph. How many feet can you travel in one second

Chemistry
1 answer:
sveticcg [70]3 years ago
6 0
5702.4 feet per sec 
might want to cross check though
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Neve later believes that New Zealand's winter is caused by the sun circling to the other side
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Explanation:

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3 0
2 years ago
Anyone know the answer
kodGreya [7K]

Answer:

a and d

Explanation:

a bromine and the calcium atom loses two elections

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3 years ago
What volume of a 0. 100mhcl stock solution should be used to prepare 250. 00ml of 0. 0250mhcl?.
Alex_Xolod [135]

62.5 mL is prepare .

What is molarity?

Molar concentration is a unit of measurement for the concentration of a chemical species, specifically a solute, in a solution, expressed as the amount of substance per unit volume of solution. The most often used unit for molarity in chemistry is the number of moles per litre, denoted by the unit symbol mol/L or mol/dm3 in SI units.

Molarity of the stock solution as 0.100 M

Volume of the dilute solution as 250 mL

Molarity of dilute solution as 0.0250 M

We are required to calculate the Volume of the stalk solution.

Taking the volume and molarity of the stock solution to be V₁ and M₁ respectively, and volume and molarity of the dilute solution to be V₂ and M₂ respectively.

We are going to use the dilution formula;

According to the dilution formula, M₁V₁ = M₂V₂

Rearranging the formula;

V₁ = M₂V₂ ÷ M₁

   = (0.025 M × 0.25 L) ÷ 0.100 M

   = 0.0625 L

But, 1 L = 1000 mL

V₁ = 62.5 mL

Therefore, the volume of the stock solution is 62.5 mL

Learn more about molarity from given link

brainly.com/question/26873446

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3 0
1 year ago
F a sample of butene (C4H8) that has a mass of 136.6 g is combusted in excess oxygen, what is the mass of CO2 that is produced?
alukav5142 [94]

The balanced chemical reaction will be:

C4H8 + 6 O2 --> 4 CO2 + 4 H2O

We are given the amount of butene being combusted. This will be our starting point.

136.6 g C4H8 (1 mol  C4H8/ 56.11 g C4H8) (4 mol CO2/1 mol <span>C4H8</span>) ( 44.01 g CO2/ 1 mol CO2) = 428.6 g CO2
7 0
3 years ago
Read 2 more answers
Give the o.N. Of each of the elements magnesium and oxygen in the reactants and in the products 2Mg + O2=2MgO
vlada-n [284]

Answer:

2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}

Explanation:

Hello there!

In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:

2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}

Best regards!

4 0
3 years ago
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