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Lesechka [4]
3 years ago
15

Write the products of these double-replacement reaction. Then balance each equation. Ba(NO3)2 (aq) + H3PO4 (aq) ---> Barium p

hosphate is a precipitate)
Chemistry
1 answer:
Pani-rosa [81]3 years ago
4 0

Answer:

Explanation:

Step 1: RxN

Ba(NO₃)₂ (aq) + H₃PO₄ (aq) → Ba₃(PO₄)₂ (s) + HNO₃ (aq)

Step 2: Balance RxN

We need 3 Ba's on both sides.

We need 2 PO₄'s on both sides.

3Ba(NO₃)₂ (aq) + 2H₃PO₄ (aq) → Ba₃(PO₄)₂ (s) + 6HNO₃ (aq)

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What is the frequency for electromagnetic radiation with a wavelength of 3.10x10^-7 m?
vampirchik [111]

Answer:

I have the same thing it's hard

3 0
3 years ago
The measured dipole moment of a polar covalent compound is 1.11 D with a percent ionic character of 18.2%. What is the bond leng
TEA [102]

Answer:

80.2

Explanation:

we subtract 18.2 from the total percentage which is 100%

8 0
3 years ago
What’s the correct answer
Fed [463]
The correct answer is: 
_________________________________________________________
    " F  and Br , because they are in the same group" .
_________________________________________________________
Note:
_________________________________________________________
Choice [B]:  "F and Br ; because they are in the same period" ; is incorrect; since  "F" and "Br" are not in the same "period" (that is, "row").
______________________________________________________
Choice [C]:  "Na and Mg; because they are in the same group {"column"} ;  is incorrect; since:  "Na" and "Mg are NOT in the same group {"column"].
_______________________________________________________
Choice [D]:  "Na and Mg" ; because they are in the same period {"row"}; is incorrect.  Note:  "Na" and "Mg" are, in fact,  in the same period {"row"}. However, as aforementioned, {Mg and Na} are not in the same group {"column".}.  

Note:  The similiarities in physical and chemistry properties among elements are determined and organized — or tend to be so—by "groups" {"columns"} — NOT by "periods" {rows}.  
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3 0
4 years ago
Chemical formula for tin iv carbide
aniked [119]

Answer:

Explanation:

Sn(WC)2

if it is tungsten carbide this should be correct but there are many versions of carbide

Sn(MC2)2

could also be possible

the 2 next to MC should be a subscript

3 0
3 years ago
When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 24.0 g of carbon were burned in the presence of
Novosadov [1.4K]

Answer:

mass of CO2 = 88 g

Explanation:

It is stated in question that 18.7 g of oxygen remained unreacted which means that carbon is limiting reactant. Thus the amount of carbon dioxide produced depend upon the amount of carbon.

Given data:

mass of carbon = 24 g

total mass of oxygen 82.7 g

mass of unreacted oxygen = 18.7 g

mass of carbon dioxide = ?

Solution:

First of we will calculate the moles of carbon.

number of moles of carbon = mass of carbon / atomic weight

number of moles of carbon = 24 g/ 12 g/mol = 2 mol

Chemical equation:

C + O2 → CO2

now we compare the number of moles of carbon and carbon dioxide,

  C   :  CO2

  1    :    1

 2    :    2

Now we will calculate the mass of carbon dioxide from moles.

number of moles of CO2 = mass of CO2 / molar mass of CO2

2 mol × 44 g/mol = mass

mass of CO2 = 88 g

8 0
3 years ago
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