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zheka24 [161]
3 years ago
11

A projectile is shot from the edge of a cliff 80 m above ground level with an initial speed of 60 m/sec at an angle of 30° with

the horizontal. Determine the time taken by the projectile to hit the ground below.
Physics
1 answer:
Dvinal [7]3 years ago
6 0

Answer:

8 seconds

Explanation:

Answer:

Explanation:

Going up

Time taken to reach maximum height= usin∅/g

=3 secs

Maximum height= H+[(usin∅)²/2g]

=80+[(60sin30)²/20]

=125 meters

Coming Down

Maximum height= ½gt²

125= ½(10)(t²)

t=5 secs

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Explanation:

The surface of the ramp here is assumed to be the positive x-direction.

To solve this problem and find the magnitude of the force of tension, we have to analyze only the situation along the x-direction, since the force of tension lie in this direction.

There are three forces acting along the x-direction:

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We know that the magnitude of the weight is

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So its x-component is

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The net force along the x-direction can be written as

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And therefore, since the net force is 98 N, we can find the magnitude of the force of tension:

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8 0
3 years ago
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classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 128 feet per
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Answer:

t_1 = 0.28 s

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Explanation:

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here we know that

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