Answer:
The horizontal distance is 0.64 m.
Explanation:
Initial velocity, u =2.5m/s
The maximum horizontal distance is

Answer:
F = 19.1 N
Explanation:
To find the force exerted by the string on the block you use the following formula:
(1)
k: spring constant = 95.5 N/m
x: displacement of the block from its equilibrium position = 0.200 m
you replace the values of k and x in the equation (1):

Hence, the force exterted on the block is 19.1 N
Answer:
The answer to the question is
Its maximum speed is 1.54 m/s
Explanation:
Work done = Kinetic energy
0.5·m·v² = 0.5·k·x²
Where
m = mass
v = velocity
k = spring constant
x = extension of the spring
We note that Force F is given by
F = m·a
Where
a = acceleration due to gravity
= 0.153×9.8 = 1.4994 N
Equating the work done by the force to the work done on the spring gives
Work done = Force × Distance = 1.4994×x = 0.5×k÷x² = 0.5×24.7×x²
x = 1.4994÷12.35 = 0.121 m
Substituting the value of x into the equation below gives
0.5·m·v² = 0.5·k·x²
0.5×0.153×v² = 12.35×0.121²
v² = 0.182÷0.0765 = 2.379
v = 1.54 m/s