Answer:
v = 10 m/s
Explanation:
Given,
Length of the vine, l = 36 m
Angle of inclination = 31.0◦ with the vertical
acceleration due to gravity = 9.81 m/s²
Using Conservation of energy
KE = PE
![\dfrac{1}{2} mv^2 = m g h](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7D%20mv%5E2%20%3D%20m%20g%20h)
![v = \sqrt{2gh}](https://tex.z-dn.net/?f=%20v%20%3D%20%5Csqrt%7B2gh%7D)
![v = \sqrt{2 g l(1-\cos \theta)](https://tex.z-dn.net/?f=%20v%20%3D%20%5Csqrt%7B2%20g%20l%281-%5Ccos%20%5Ctheta%29)
![v = \sqrt{2\times 9.81\times 36 \times (1-\cos 31^0)](https://tex.z-dn.net/?f=%20v%20%3D%20%5Csqrt%7B2%5Ctimes%209.81%5Ctimes%2036%20%5Ctimes%20%281-%5Ccos%2031%5E0%29)
v = 10 m/s
Hence, the speed of the swing is equal to 10 m/s
The vertical velocity is the greatest at C, where it is closest to the ground.
The projectiles horizontal velocity stays constant through the entire thing, so it is the same for A, B, and C.
The projectiles speed is the greatest at C, because both its vertical and horizontal components of its velocity is greater than or equal to that of the other two points.
<h2>
<u>ANSWER</u><u>:</u></h2>
<h3>
<u>C</u><u>.</u><u> </u><u>1</u><u>0</u><u>0</u><u> </u><u>NEWTONS</u></h3>
<h2>
<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u></h2>
<u>CARRY</u><u> </u><u>ON</u><u> LEARNING</u>
<u>CAN</u><u> </u><u>Y</u><u>OU</u><u> BRAINLEST</u><u> ME</u>
Answer:
I think the answer is b but i cannot confirm cuz this is a challenging question