All categories

3 years ago

The current in a lightning bolt is 2.6 x 105

Physics

1 answer:

Harman [31]3 years ago

4 0

Answer:

The right solution is " $10.66\times 10^5 \ C$ ". A further explanation is given below.

Explanation:

The given values are:

Current,

I = $2.6\times 10^5$

Time,

t = 4.1 s

As we know,

⇒ $Q=I\times t$

On substituting the given values, we get

⇒ $=2.6\times 10^5\times 4.1$

⇒ $=1,066,000 \ C$

⇒ $=10.66\times 10^5 \ C$

You might be interested in

How long does it take an automobile traveling 66.7 km/h to become even with a car that is traveling in another lane at 52.7 km/h

tresset_1 [31]

Answer:

The time taken is $t = 32.5 \ s$

Explanation:

From the question we are told that

The speed of first car is $v_1 = 66.7 \ km/h = 18.3 \ m/s$

The speed of second car is $v_2 = 52.7 \ km/h = 14.64 \ m/s$

The initial distance of separation is $d = 119 \ m$

The distance covered by first car is mathematically represented as

$d_t = d_i + d_f$

Here $d_i$ is the initial distance which is 0 m/s

and $d_f$ is the final distance covered which is evaluated as $d_f = v_1 * t$

$d_t = 0 \ m/s + (v_1 * t )$

$d_t = 0 \ m/s + (18.3 * t )$

The distance covered by second car is mathematically represented as

$d_t = d_i + d_f$

Here $d_i$ is the initial distance which is 119 m

and $d_f$ is the final distance covered which is evaluated as $d_f = v_2* t$

$d_t = 119 + 14.64 * t$

Given that the two car are now in the same position we have that

$119 + 14.64 * t = 0 + (18.3 * t )$

$t = 32.5 \ s$

6 0

2 years ago

Michael Scott is driving through the parking lot and accidentally hits Meredith as she’s walking to her car. If his car makes co

fiasKO [112]

Yes she's dead or in the hospital

6 0

3 years ago

A typical jet airliner has a cruise airspeed of 900 km/h , which is its speed relative to the air through which it is flying. If

Luba_88 [7]

Explanation:

It is given that,

Speed of the jet airplane with respect to air, $v_{PA} = 900\ km/h$

If the wind at the airliner’s cruise altitude is blowing at 100 km/h from west to east, $v_{AG}= 100\ km/h$

(A) Let $v_{PG}$ is the speed of the airliner relative to the ground if the airplane is flying from west to east,

$v_{PG}=900-100=800\ km/h$

(B) Let $v'_{PG}$ is the speed of the airliner relative to the ground if the airplane is flying from east to west,

$v'_{PG}=900+100=1000\ km/h$

Hence, this is the required solution.

8 0

3 years ago

Q 2 Two mirrors meet at right angles. A ray of light is incident on one at an angle of 30°

serg [7]

a ray of light is incident towards a plane mirror at an angles of 30degrees with the mirror surface. what will be the angles of reflection is 60degree.

3 0

2 years ago

Match the following moves to the correct total distance and displacement of the moves.

MAVERICK [17]

A. Move 2 m east and then 12 m east; displacement is 14 m east and the distance is 14 m
B. Move 10 m east and then 12 m west, the displacement is 2 m west and the distance is 22 m.
C. Move 8 m west and then 16 m east; the displacement is 8 m east and the distance is 24 m
D. Move 12 m west and then 8 m east; the displacement is 4 m and the distance is 20 m

5 0

3 years ago