A pump steadily delivers water through a hose terminated by a nozzle. The exit of the nozzle has a diameter of 0.6 cm and is loc
ated 10 m above the pump inlet pipe, which has a diameter of 1.2 cm. The pressure is equal to 1 bar at both the inlet and the exit, and the temperature is constant at 20C. The magnitude of the power input required by the pump is 1.5 kW, and the acceleration of gravity is g 9.81 m/s2 . Determine the mass flow rate delivered by the pump, in kg/s
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Answer:
The total distance traveled by the car (S) = 15 mi
Explanation:
Total acceleration () = 10 mi /
Time (t) = 1 hour
Deceleration () = - 5 mi /
From law of speed we know that V = u + t -----------(1)
Where V = Final speed
u = initial speed and t = time period
Car starts from rest so initial speed is zero so u = 0
Then equation 1 becomes V = t = 10 × 1 = 10 mi / h ---------(2)
The distance traveled by the car = u t +
×
×
-------------(3)
Put all the values in equation we get = 0 +
× 10 ×
= 5 mi ---------------(4)
This is the distance traveled by the car in 1 hour.
In second case when car starts decelerates the equation of motion becomes
⇒ V = u - a t -----------(5)
final speed in this case = 0 and initial speed (u) = 10 mi / h
⇒ 0 = 10 - 5 t
⇒ 5 t = 10
⇒ t = 2 hours
Distance traveled by the car in to hours = u t +
×
×
⇒ = 10 × 2 -
× 5 ×
⇒ = 20 - 10
⇒ = 10 mi
This is the distance traveled by the car in the next two hours.
Thus the total distance traveled by the car = +
⇒ S = 5 + 10 = 15 mi