Answer:
the angular acceleration of the car is 1.5 rad/s²
Explanation:
Given;
initial angular velocity,
= 10 rad/s
final angular velocity,
= 25 rad/s
time of motion, t = 10 s
The angular acceleration of the car is calculated as follows;

Therefore, the angular acceleration of the car is 1.5 rad/s²
Answer:
The height of Sears Tower is 1448.5 feet.
Explanation:
<h3>
We apply the free fall formula to the ball:
</h3><h3>

</h3><h3>y: The vertical distance the ball moves at time t </h3><h3>

i: Initial speed
</h3><h3>g=Gravity acceleration=

</h3>
Known information
We know that the vertical distance (y) that the ball moves in 9,5s is equal to height of Sears Tower (h).
Too we know that the ball is released from rest, then,
=0
Height of Sears Tower calculation:
We replace in the equation 1 the data following;






Answer: The height of Sears Tower is 1448.5 ft
Answer:
5.95 m
Explanation:
Given that the biggest loop is 40.0 m high. Suppose the speed at the top is 10.8 m/s and the corresponding centripetal acceleration is 2g
For the car to stick to the loop without falling down, at the top of the ride, the centripetal force must be equal to the weight of the car. That is,
(MV^2) / r = mg
V^2/ r = centripetal acceleration which is equal to 2g
2 × 9.8 = 10.8^2 / r
r = 116.64 /19.6
r = 5.95 m
We use the formula,
m = V\rho
Here, m is the mass, V is the volume and
density
Also

Here l is length, w is width and h is height.
(a) The volume of the room,

The volume of the room in cubic feet,

(b) Now the mass of the air in room,
.
Therefore, the weight of the air in room,
.
The weight of air in the room in pounds,

GPE= height x mass x gravitational field strength
5 x 10 x 9,8=490J