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4 years ago

Define what is meant by restrictive interventions

Physics

1 answer:

zzz [600]4 years ago

5 0

Medical movement for disabilities people

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Suppose you stand on the rim of a space station. If the radius of the station is 12,000

ale4655 [162]

Answer:

circle

Explanation:

because Earth is not oblong

8 0

3 years ago

light of wavelength 520 nm falls on a slit that is 3.20 um wide. Estimate how far the first bright-sh difrrection fringe is

Westkost [7]

Answer:

because of the gravity of the earth

6 0

2 years ago

A slender rod is 80.0 cm long and has mass 0.390 kg . A small 0.0200-kg sphere is welded to one end of the rod, and a small 0.05

Lilit [14]

Answer:

v = 1.08 m/s

Explanation:

What is the linear speed of the 0.0500-kg sphere as its passes through its lowest point?

The decrease in PE is

d = 80.0cm * 1 / 1000m = 0.80m

h = 0.80 m /2 = 0.40 m

ΔPE = m*g*h

ΔPE = (0.0500 - 0.0200)kg * 9.8m/s² * 0.400 m

ΔPE = 0.1176 J

The moment of inertia of the assembly is

I = 1/12*m*L² + (m1 + m2)*(L/2)²

I = 1/12*0.390kg*(0.800m)² + 0.0700kg*(0.400m)²

I = 0.032 kg·m²

KE = ½Iω²

0.1176 J = ½ * 0.032kg·m² * ω²

ω = 2.71 rad/s

v = ωr = 2.71 rad/s * 0.400m

The linear velocity

v = 1.08 m/s

3 0

3 years ago

5 ways in which people can explore space without physically <br> going there

goblinko [34]

Telescope
books
drawings
satellites
images taken from rockets

i hope these help and that there right!!

8 0

3 years ago

A conducting rod is moving through a magnetic field, as in the drawing. The magnetic field strength is 0.65 T, and the speed of

Contact [7]

Explanation:

The given data is as follows.

Magnetic field strength (B) = 0.65 T

Speed (v) = 2.3 m/s

Induced emf (E) = ?

Formula for emf induced at the ends of the rod of length L which is moving with a speed of v is as follows.

E = BvL

Putting the given values into the formula as follows.

$E_{1} = BvL$

= $0.65 T \times 2.3 m/s \times L$

= 1.495 L .............. (1)

When magnetic field is changed to $B_{2}$ = 0.48 T

Now, we assume that the speed be $v_{2}$ to get the emf $E_{2} = E_{1}$ .

Then, $0.48 T \times v_{2} \times L = 0.65 T \times 2.3 m/s \times L$

$v_{2}$ = 3.11 m/s

Therefore, we can conclude that the speed v of the rod be adjusted to reestablish the emf induced between the ends of the rod at its initial value is 3.11 m/s.

6 0

3 years ago