Question

A car goes from 4.47 m/s to 17.9 m/s in 3 seconds. calculate the acceleration of the car

Answer 1

Answer:

4.48 m/s²

Explanation:

Acceleration is change in velocity over time.

a = Δv / Δt

a = (17.9 m/s − 4.47 m/s) / 3 s

a = 4.48 m/s²

Answer 2

Answer:

$\boxed {\tt a \approx4.48 \ m/s^2}$

Explanation:

Acceleration can be found by dividing the change in velocity over the time.

$a=\frac{\Delta v}{t}$

The change in velocity can be found by subtracting the final velocity by the initial velocity.

$\Delta v= final \ velocity - initial \ velocity$

The final velocity is 17.9 meters per second.

The initial velocity is 4.47 meters per second.

$\Delta v=17.9 \ m/s-4.47 \ m/s$

$\Delta v=13.43 \ m/s$

The change in velocity is 13.43 meters per second and the time is 3 seconds.

$a=\frac{13.43 \ m/s}{3 \ s}$

Divide.

$a=4.47666667 \ m/s^2$

$a \approx4.48 \ m/s^2$

The acceleration is about 4.48 meters per seconds squared.