When unequal resistors are connected in series across an ideal battery,the same power is dissipated in each one.the potential di
1 answer:
Answer:
the current flowing in each is the same.
Explanation:
When resistors are connected in series, they are connected in the same branch of the circuit - this means that the same current flows through each resistor.
The other options listed are wrong because:
the same power is dissipated in each one --> false: the power dissipated in each resistor is , where I is the current and R the resistance, so it depends on the value of the resistance
the potential difference across each is the same.-- > false: this is true in parallel circuits, not series circuits
the equivalent resistance of the circuit is less than that of the smallest resistor.--> false: the equivalent resistance of a series circuit is the sum of the individual resistances: , so it is larger than the resistance of the smallest resistance
the equivalent resistance of the circuit is equal to the average of all the resistances. --> false: the equivalent resistance of a series circuit is the sum of the individual resistances: , not the average
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Answer:
- It can be infer that it has a lower frequency.
<em>In the case of electromagnetic waves.</em>
- A short wavelength means a lower energy,
Explanation:
The wavelength is the distance between two consecutive crests or valleys while the frequency is the number of crests that pass for a specific point in an interval of time.
For example, a person makes laundry once a weak.
In this example, the event is represented by the laundry and the interval of time is once a weak
The velocity of a wave is defined as:
(1)
Where is the frequency and
is the wavelenth
(2)
Notice from equation 2 that the wavelength is inversely proportional to the frequency (when the wavelength increases the frequency decreases).
In the case of electromagnetic waves, a short wavelength means a lower energy, as it can be seen in equation 4 (inversely proportional).
(3)
(4)
Answer
given,
focal length of lens A = 5.77 cm
focal length of lens B= 27.9 cm
flies distance from mirror = 11.3 m
now,
Using lens formula
q =11.79 cm
image of lens A is object of lens B
distance of lens = 59.9 - 11.79 = 48.11
now, Again applying lens formula
q' =66.41 cm
hence, the image distance from the second lens is equal to q' =66.41 cm
a) For the motion of car with uniform velocity we have , , where s is the displacement, u is the initial velocity, t is the time taken a is the acceleration.
In this case s = 520 m, t = 223 seconds, a =0
Substituting
The constant velocity of car a = 2.33 m/s
b) We have
s = 520 m, t = 223 seconds, u =0 m/s
Substituting
Now we have v = u+at, where v is the final velocity
Substituting
v = 0+0.0209*223 = 4.66 m/s
So final velocity of car b = 4.66 m/s
c) Acceleration = 0.0209