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jeka94
3 years ago
7

Select all the correct answers.

Physics
1 answer:
sdas [7]3 years ago
5 0
I believe there are two correct answers, and those answers are A and D
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A fire hose has an inside diameter of 6.40 cm. Suppose such a hose carries a flow of 40.0 L/s starting at a gauge pressure of 1.
inessss [21]

Answer:

The Reynolds numbers for flow in the fire hose.

Explanation:

Given that,

Diameter = 6.40 cm

Rate of flow = 40.0 L/s

Pressure P=1.62\times10^{6}\ N/m^2

We need to calculate the Reynolds numbers for flow in the fire hose

Using formula of rate of flow

Q=Av

v=\dfrac{Q}{A}

Where, Q = rate of flow

A = area of cross section

Put the value into the formula

v=\dfrac{40.0\times10^{-3}}{3.14\times(3.2\times10^{-2})^2}

v=12.44\ m/s

We need to calculate the Reynolds number

Using formula of the Reynolds number

n_{R}=\dfrac{2\rho\times v\times r}{\eta}

Where, \eta =viscosity of fluid

\rho =density of fluid

Put the value into the formula

n_{R}=\dfrac{2\times100\times12.44\times3.2\times10^{-2}}{1.002\times10^{-3}}

n_{R}=7.945\times10^{5}

Hence, The Reynolds numbers for flow in the fire hose.

3 0
3 years ago
It is easier to add vectors together if we split them into what? A. Sizes B. Components C. Quadrants D. Lines
jonny [76]

Answer:

<h2> B. Components</h2>

Explanation:

Splitting vectors into components makes it easier to perform operations on them, typically categorizing vectors into horizontal and vertical components which are the two components makes it very easy to perform operations, since they are similar terms and operations cab be done easily

7 0
4 years ago
What type of fossils were found near Macon Georgia?
den301095 [7]

Answer:

I believe whale fossils were found.

7 0
3 years ago
Read 2 more answers
__________ is the most important consideration in stopping a vehicle.
xxTIMURxx [149]
FRICTION is the most important consideration in stopping a vehicle. Stopping a vehicle involves three elements which are brake, tires and the surface with which the car is in contact. Frictional forces between the car tires and the surface contact when the brake is applied stop the car. 
5 0
4 years ago
An aluminum "12 gauge" wire has a diameter d of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The el
Alborosie

Answer:

I = 4.75 A

Explanation:

To find the current in the wire you use the following relation:

J=\frac{E}{\rho}      (1)

E: electric field E(t)=0.0004t2−0.0001t+0.0004

ρ: resistivity of the material = 2.75×10−8 ohm-meters

J: current density

The current density is also given by:

J=\frac{I}{A}        (2)

I: current

A: cross area of the wire = π(d/2)^2

d: diameter of the wire = 0.205 cm = 0.00205 m

You replace the equation (2) into the equation (1), and you solve for the current I:

\frac{I}{A}=\frac{E(t)}{\rho}\\\\I(t)=\frac{AE(t)}{\rho}

Next, you replace for all variables:

I(t)=\frac{\pi (d/2)^2E(t)}{\rho}\\\\I(t)=\frac{\pi(0.00205m/2)^2(0.0004t^2-0.0001t+0.0004)}{2.75*10^{-8}\Omega.m}\\\\I(t)=4.75A

hence, the current in the wire is 4.75A

4 0
3 years ago
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