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Vlad1618 [11]
3 years ago
8

A 5 kg object slows from +6 m/s to +2 m/s. What is the impulse?

Physics
1 answer:
Liula [17]3 years ago
5 0

Impulse on the object: -20 kg m/s

Explanation:

The impulse exerted on an object is a vector quantity equal to the product between the force exerted on the object and the time interval during which the force is applied.

The impulse exerted on an object is also equal to its change in momentum. Mathematically,

I=\Delta p = m(v-u)

where:

m is the mass of the object

u is the initial velocity

v is the final velocity

For the object in this problem, we have

m = 5 kg

u = +6 m/s

v = +2 m/s

Therefore, its impulse is:

I=(5)(+2-(+6))=-20 kg m/s

The negative sign means the direction of the impulse is opposite to the direction of motion of the object.

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

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Answer:

The change in momentum = -20000 kg m/s.

Explanation:

Mass m = 1000 kg

speed v₁ = 20 m/s

speed v₂ = 0 m/s

We know that,

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ΔP = m (Δv)

ΔP = m (v₂ - v₁)

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Thus, the change in momentum = -20000 kg m/s.

Note: negative sign indicates that the velocity is reducing when it hits the barrier.

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C

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What happened to the balloon when it was placed on the bottle with the baking soda and vinegar and why.
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Acids such as acetic acid react with carbonate salts. One of the products of such reactions is carbon dioxide {\rm CO_{2}}, a gas.

In this question, when the acetic acid in vinegar reacts with sodium bicarbonate in the baking soda, the following reaction would occur:

\begin{aligned}& {\rm Na_{2}CO_{3}}\, (aq) + 2\, {\rm CH_{3}COOH}\, (aq) \\ &\to 2\, {\rm CH_{3}COONa}\, (aq) + {\rm CO_{2}}\, (g)\end{aligned}.

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Answer:

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