Answer:
1.9 × 10² g NaN₃
1.5 g/L
Explanation:
Step 1: Write the balanced decomposition equation
2 NaN₃(s) ⇒ 2 Na(s) + 3 N₂(g)
Step 2: Calculate the moles of N₂ formed
N₂ occupies a 80.0 L bag at 1.3 atm and 27 °C (300 K). We will calculate the moles of N₂ using the ideal gas equation.
P × V = n × R × T
n = P × V / R × T
n = 1.3 atm × 80.0 L / (0.0821 atm.L/mol.K) × 300 K = 4.2 mol
We can also calculate the mass of nitrogen using the molar mass (M) 28.01 g/mol.
4.2 mol × 28.01 g/mol = 1.2 × 10² g
Step 3: Calculate the mass of NaN₃ needed to form 1.2 × 10² g of N₂
The mass ratio of NaN₃ to N₂ is 130.02:84.03.
1.2 × 10² g N₂ × 130.02 g NaN₃/84.03 g N₂ = 1.9 × 10² g NaN₃
Step 4: Calculate the density of N₂
We will use the following expression.
ρ = P × M / R × T
ρ = 1.3 atm × 28.01 g/mol / (0.0821 atm.L/mol.K) × 300 K = 1.5 g/L
The percent by mass of an answer made from 14 g NaCl (the solute) and 61 g water is 18.66%
14 g + 61 g =75.0 g - mass of the solution
mass % = (mass solute/ mass solution)*100% = (14/75.0)*100% =
= 0.186*100% =18.66%.
What is the percent by mass?
Mass percent is another method of expressing the composition of the solution mixture. It describes the amount of solute (grams) present in 100 gm of the solution.
To know more about percent by mass go to the given link :
brainly.com/question/20393858
Its location is in the nucleus, because the particle is a proton or a neutron.
A(g) ⇄ 2 B(g)
Initial 1.32 0
Change -1.07 + 2.14
Equilibrium 0.25 2.14
Kp = P²
/ P
= (2.14)² / 0.25 = 18.3
Note that:
Change of A is calculated by (1.32 - 0.25 = 1.07)
also change in B is calculated by multiplying change of A times 2
