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3 years ago

Which characteristic cannot be inherited?

Chemistry

2 answers:

lana66690 [7]3 years ago

4 0

Answer:

Knowledge of facts

Explanation:

All of these are inherited traits: Color, Height, and Shape

but Knowledge is a learnt trait

evablogger [386]3 years ago

3 0

Answer:

The knowledge of Facts

Explanation:

Knowledge cannot be inherited from your parents. It is something you obtain on your own. However, the color of an animals fur, the height of a plant, and the shape of a face are all passed down genetically.

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You are given a cup of milk and a spoon of sugar. What type of mixture will be formed? justify your answer.

IrinaK [193]

Milk that’s really sweet? or clumpy milk?

6 0

3 years ago

Consider three gases: Ar, SF6, and Cl2. If 50.0 grams of these gases are placed in each of three identical containers, which con

adoni [48]

The ideal gas law:
$pV=nRT \Rightarrow p=\frac{nRT}{V}$
p - pressure, n - number of moles, R - the gas constant, T - temperature, V - volume

The volume and temperature of all three containers are the same, so the pressure depends on the number of moles. The greater the number of moles, the higher the pressure.
The mass of gases is 50 g.

$Ar \\
M \approx 39.948 \ \frac{g}{mol} \\
n=\frac{50 \ g}{39.948 \ \frac{g}{mol}} \approx 1.25 \ mol \\ \\
SF_6 \\
M \approx 146.06 \ \frac{g}{mol} \\
n=\frac{50 \ g}{146.06 \ \frac{g}{mol}} \approx 0.34 \ mol \\ \\
Cl_2 \\
M=70.9 \ \frac{g}{mol} \\
n=\frac{50 \ g}{70.9 \ \frac{g}{mol}} \approx 0.71 \ mol$

The greatest number of moles is in the container with Ar, so there is the highest pressure.

4 0

3 years ago

The normal boiling point of methanol is 64.7 ∘ C and the molar enthalpy of vaporization is 71.8kJ/mol . The value of ΔS when 1.3

guapka [62]

Answer:

286 J/K

Explanation:

The molar Gibbs free energy for the vaporization (ΔGvap) is:

ΔGvap = ΔHvap - T.ΔSvap

where,

ΔHvap: molar enthalpy of vaporization

T: absolute temperature

ΔSvap: molar entropy of the vaporization

When T = Tb = 64.7 °C = 337.9 K, the reaction is at equilibrium and ΔGvap = 0.

ΔHvap - Tb . ΔSvap = 0

ΔSvap = ΔHvap/Tb = (71.8 × 10³ J/K.mol)/ 337.9 K = 212 J/K.mol

When 1.35 mol of methanol vaporizes, the change in the entropy is:

$1.35mol.\frac{212J}{K.mol} =286 J/K$

7 0

3 years ago

Consider the following exothermic reaction and predict how the change below will affect the concentration (increase, decrease, s

aev [14]

Answer:

a) equilibrium shifts towards the left

b) equilibrium shifts towards the right hand side.

c)equilibrium shifts towards the left hand side

d) addition of argon has no effect on the equilibrium position

e) equilibrium position shifts towards the left hand side

f) equilibrium position is shifted towards the right hand side

g) addition of a catalyst has no effect on the equilibrium position

Explanation:

Given the equation;

3N2H4(g)⇄ 4NH3 (g) + N2 (g)

Adding N2

The addition of N2 will increase the concentration of N2 in the system thereby shifting the equilibrium position to the left in accordance with Le Chatelier's principle.

Removing N2

The removal of N2 drives the forward reaction and the equilibrium shifts towards the right yielding more N2 in accordance with Le Chateliers principle.

Add NH3

The addition of NH3 will shift the equilibrium position towards the left hand side according to Le Chateliers principle.

d) addition of argon has no effect on the equilibrium position.

e) increasing the temperature

Since the reaction is exothermic, increasing the temperature favours the reverse reaction and the equilibrium position his shifted towards the left hand side.

f) Decrease in volume;

Decreasing the volume favours the forward reaction hence the equilibrium position is shifted towards the right.

g) addition of a catalyst has no effect on the equilibrium position.

3 0

2 years ago

At what temperature will 55 grams of chlorine gas Cl2 exert a pressure of 245 kPa at a volume of 3.4 liters?

DiKsa [7]

132.67 K is the temperature at which 55 grams of chlorine gas exert a pressure of 245 kPa at a volume of 3.4 liter.

Explanation:

Data given:

mass of chlorine gas = 55 grams

atomic mass of chlorine gas = 71 grams/mole

pressure of chlorine gas = 245 kPa 0R 2.41 atm

volume of the chlorine gas = 3.4 litres

temperature of the chlorine gas = ?

R = 0.08201 Latm/moles K

n =?

Assuming that chlorine behaved like ideal gas, the formula used will be,

PV = nRT

number of moles = $\frac{mass}{atomic mass of 1 mole}$

number of moles= $\frac{55}{71}$

number of moles = 0.77

putting the values in ideal gas equation:

T = $\frac{2.41 X 3.4}{0.08021 X 0.77}$

T = 132.67 K

temperature is 132.67 K

3 0

3 years ago