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The charge distribute on the inner surface with the radius r₁ will be zero,In the region r₁<r<r₂ will also zero. While on the outer surface with radius r₂ will be -q.
<h3>What is Gauss law?</h3>
The total electric flux out of a closed surface is equal to the charge contained divided by the permittivity,
According to Gauss Law. the electric flux in a given area is calculated by multiplying the electric field by the area of the surface projected in a plane perpendicular to the field.
From the Gauss law, it is stated that the field inside the conductor is zero. Charge will lie only on the surface.
(a)The charge distribute on the inner surface with the radius r₁ will be zero.
(b) In the region r₁<r<r₂ will also zero.
(c)The outer surface with radius r₂ charge distribution will be -q.
Hence, the charge distribute on the inner surface with the radius r₁ will be zero,
To learn more about the Gauss law, refer to the link;
brainly.com/question/2854215
#SPJ1
Answer:
The x-component of the electric field at point P -- 31,638.41
Explanation:
Given data:
charge density 
Another charge density 
Electric field due to infinite sheet of charge is given as E
= 31,638.41
