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givi [52]
3 years ago
13

A chemist dissolves 614. mg of pure hydrochloric acid in enough water to make up 400 mL of solution. Calculate the pH of the sol

ution. Round your answer to 3 significant decimal places. X 5 ? 1 Don't Know Suomi
Chemistry
1 answer:
tatuchka [14]3 years ago
7 0

Answer:

The pH of the solution is 1.38.

Explanation:

Mass of HCl = 614 mg = 0.614 g

Moles of HCl = \frac{0.614 g}{36.5 g/ mol}=0.01682 mol

Concentration of HCl :

Concentration =\frac{Moles}{\text{Volume of solution in L}}

On adding 0.01682 moles to 400 mL of water that 0.4 L of water.

[HCl]=\frac{0.01682 mol}{0.4 L}=0.04205 M

HCl(s)+H_2O(l)\rightarrow H_3O^+(aq)+Cl^-(aq)

1 mole of HCl gives 1 mole of hydronium ion and 1 mole of chloride ions in an aqueous solution.

Then 0.04205 mol/L of HCl will give:

1\times 0.04205 M =0.04205 mol/L of hydronium ions.

[H_3O^+]=0.04205 M

pH=-\log [H_3O^+]

pH=-\log [0.04205 M]=1.38

The pH of the solution is 1.38.

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Also, Moles is given as,

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Data Given;

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                              Mass  =  2.8 mol.L⁻¹ × 101.5 g.mol⁻¹ × 1 L

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