A chemist dissolves 614. mg of pure hydrochloric acid in enough water to make up 400 mL of solution. Calculate the pH of the sol
1 answer:
Answer:
The pH of the solution is 1.38.
Explanation:
Mass of HCl = 614 mg = 0.614 g
Moles of HCl =
Concentration of HCl :
On adding 0.01682 moles to 400 mL of water that 0.4 L of water.
1 mole of HCl gives 1 mole of hydronium ion and 1 mole of chloride ions in an aqueous solution.
Then 0.04205 mol/L of HCl will give:
of hydronium ions.
The pH of the solution is 1.38.
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