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hram777 [196]
3 years ago
6

*zoom in if you can’t see*PLEASE HELP!!! FASTTT!!!

Mathematics
1 answer:
snow_tiger [21]3 years ago
6 0

Answer:

D is the answer.

Step-by-step explanation:

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0.4x + 28.5 = 281 Solve for x.
mash [69]

Answer:

Step-by-step explanation:

281-28.5=252.5

252.5 divided by 0.4=631.25

X=631.25

6 0
3 years ago
Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!
LUCKY_DIMON [66]

Answer:

=8\sqrt{15}b^{\frac{7}{2}}

Step-by-step explanation:

\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}

=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}

=\sqrt{40}b^2\sqrt{24b^3}

\sqrt{24b^3}

=\sqrt{24}\sqrt{b^3}

=\sqrt{24}b^{\frac{3}{2}}

=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

\sqrt{2^3}

=2^{3\cdot \frac{1}{2}

=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}

2^{\frac{3}{2}+\frac{3}{2}}

=2^3

=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}

b^{\frac{3}{2}+2}

=b^{\frac{7}{2}}

=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}

=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}

=8\sqrt{15}b^{\frac{7}{2}}

4 0
3 years ago
Just need the answers for these 3 questions please, and how to do them (:
Darya [45]

Answer:

a) 7

b)64

c)2

Step-by-step explanation:

look at images

6 0
3 years ago
Read 2 more answers
Evaluate 7w -14 for w=9
densk [106]
It is 49. 7(9) -14 is 49.
5 0
4 years ago
Find equation of the perpendicular to the line x + 2 y – 4 and passes through<br> point (2,1)
Allushta [10]

Answer:

y = 2x - 3

Step-by-step explanation:

x + 2y = 4

2y = -x + 4

y = -1/2x + 2

1 = 2(2) + b

1 = 4 + b

-3 = b

y = 2x - 3

3 0
3 years ago
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