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3 years ago

How to find power of each resistor in a parallel circuit

2 answers:

7 0

The sum of the currents through each path is equal to the total current that flows from the source. You can find total resistance in a Parallel circuit with the following formula: 1/Rt = 1/R1 + 1/R2 + 1/R3 +... If one of the parallel paths is broken, current will continue to flow in all the other paths.

lesya692 [45]3 years ago

6 0

The power dissipated by each be found using any of the equation relating power currents voltage and resistance

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Scientists usually write reports about their investigations. Why do they do this?

worty [1.4K]

As for me, the reson why scientists usually write reports about their investigations is because they want to <span>d. to communicate their work to other scientist. As far as I am concerned in this sphere they have to get many other opnions besides their own in order to complete or expand one that they have made up. Hope it helps :)</span>

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3 years ago

What is the pooled variance for the following two samples?

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I think it is B as 168/20

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3 years ago

A 5.0 mm diameter proton beam carries a total current of 1.5mA. The current density in the proton beam, which increases with dis

slavikrds [6]

Answer:

Jedge = 0.076A/cm^2

Explanation:

If you want to know what is Jedge is convenient to use an integral. The total density current is given by:

$J_T=\int_{0}^{R}J_{edge}(\frac{r}{R})dr=J_{edge}(\frac{1}{R})(\frac{R^2}{2})=\frac{J_{edge}R}{2}$ (1)

But also, we have that the total current is

$I_T=J_TA\\\\J_T=\frac{I_T}{A}=\frac{1.5*10^{-3}A}{\pi(5*10^{-3})^2}=19.09\frac{A}{m^2}$

where we have used that 5mm=5*10^{-3}m.

By replacing (1) we obtain:

$J_{edge}=\frac{2J_T}{R}=\frac{2(19.09A/m^2)}{5*10^{-3}m}=7639.4\frac{A}{m^2}=0.076\frac{A}{cm^2}$

hope this helps!!

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4 years ago

Read 2 more answers

. Suppose an electron is chasing a proton up this page when suddenly a magnetic field pointing into the page is applied. What wo

irina1246 [14]

The proton and electron experience forces to the left and right of the page, the particles would separate to the left and right respectively after the magnetic field is applied.

To know what would happen to each particle when a magnetic field pointing in the direction of the page is applied, we need to know the direction of the force acting on the particles due to this magnetic field according to fleming's left hand rule

<h3>What is Fleming's left hand rule?</h3>

This states that when the thumb, the middle-finger and fore-finger of the left-hand are held at right angles to each other, the magnetic field points in the direction of the fore-finger, the current (or direction of charge) points in the direction of the middle finger and the force on the conductor or charge points in the direction of the thumb.

<h3>What is the direction of force on the proton?</h3>

Since the direction of the proton is up the page and the direction of the magnetic field is into the page, the direction of the force according to fleming's left hand rule is to the left of the page.

<h3>What is the direction of force on the electron?</h3>

Since the direction of the electron is up the page (it is in the direction of the conventional current or positive charge in the other direction) and the direction of the magnetic field is into the page, the direction of the force according to fleming's left hand rule is to the right of the page.

Since both the proton and electron experience forces to the left and right of the page, the particles would separate to the left and right respectively after the magnetic field is applied.

Learn more about magnetic field here:

brainly.com/question/26051825

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2 years ago

Describe how you will show J. J. Thomson's model of the atom using small beads and clay

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You would make rings of clay and then place the beads on the rings (one on each) at various places and one in the center for the nucleus.

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3 years ago