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dangina [55]
4 years ago
5

Ramon and sally are observing a toy car speed up as it goes around a circular track. ramon says, "the car's speeding up, so ther

e must be a net force parallel to the track." "i don't think so," replies sally. "it's moving in a circle, and that requires centripetal acceleration. the net force has to point to the center of the circle."
Physics
1 answer:
Anestetic [448]4 years ago
4 0
The changing speed demonstrates the nearness of an increasing speed; this centripetal quickening is of enduring with significance and coordinated in any regard cases toward the hub of the pivot. This increasing speed is, thus, created by utilizing a centripetal anxiety that is furthermore reliable in significance and coordinated toward the hub of revolution. contained in regards to revolution around a settled hub of a firm build that is not irrelevantly little in contrast with the span of the course, each and every molecule of the constitution portrays a uniform around activity with the equivalent rakish speed, yet with speed and increasing speed different with the range with comprehend to the hub.
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Do black holes have an internal structure? If so, how might the internal structure be probed?
oksian1 [2.3K]

Answer:

no

Explanation:

it can't be probed it would be like probing a goat's butt

5 0
3 years ago
Read 2 more answers
A sanding disk with rotational inertia 3.8 x 10-3 kg·m2 is attached to an electric drill whose motor delivers a torque of magnit
Elis [28]

Answer:

(a) Angular momentum of disk is 1.343\, \frac{kg.m^{2}}{s}

(b) Angular velocity of the disk is 353\frac{rad}{s}

Explanation:

Given

Rotational inertia of the disk , I=3.8\times 10^{-3}kg.m^{2}

Torque delivered by the motor , \tau =17N.m

Torque is applied for duration , \Delta t=79ms=0.079s

(a)

Magnitude of angular momentum of the disk = Angular impulse produced by the torque

\therefore L=\tau \Delta t=17\times 0.079\frac{kg.m^{2}}{s}

=>L=1.343\, \frac{kg.m^{2}}{s}

Thus angular momentum of disk is 1.343\, \frac{kg.m^{2}}{s}

(b)

Since Angular momentum , L=I\omega

where \omega= Angular velocity of the disk

=>\omega =\frac{L}{I}=\frac{1.343}{3.8\times 10^{-3}}\frac{rad}{s}

\therefore \omega =353\frac{rad}{s}

Thus angular velocity of the disk is 353\frac{rad}{s}

5 0
3 years ago
You have three identical resistors that you can connect in various ways. Which of the following is NOT a possible value of the e
Snezhnost [94]

Answer: option c.

Explanation: 3 identical resistors can only have 3 configurations

1) all 3 resistors in series

2) all 3 resistors in parallel

3) 2 parallel resistors in series with 1 resistor.

Case 1 : all 3 resistors in series

Let us assume each of the resistor has resistance value R.

The total resistor (Rt) of 3 resistors in series is given as

Rt = R1 + R2 + R3

Since R1=R2=R3=R

Rt = R+R+R = 3R.

Case 2: all 3 resistors in parallel.

The equivalent resistance of resistors in parallel is given by the formulae below.

1/Rt = 1/R1 + 1/R2 + 1/R3

Since R1=R2=R3=R

1/Rt = 1/R + 1/R + 1/R

1/Rt = 1 +1 +1/ R

1/Rt = 3/R

3 * Rt = R

Rt = R/3

Case 3: 2 parallel resistor in series with one

First is to get the equivalent resistance of the 2 parallel resistor.

1/Rt = 1/R1 + 1/R2

But R1=R2=R

1/Rt = 1/R + 1/R

1/Rt = 1 + 1/R

1/Rt = 2/R

2 *Rt = R

Rt =R/2.

R/2 in series with R has an equivalent resistance as shown below

Rt = R/2 + R

Rt = R + 2R/2

Rt = 3R/2

Since all the possible 3 configuration are listed above and there is no other then option c ( 2R/3) is not possible to achieve

4 0
4 years ago
24- What happens to a given mass of water as it is cooled from 4°C to zero?
QveST [7]

Explanation:

A-It starts to expand. Hence ice and water of same weight has different volumes

6 0
3 years ago
A reasonable walking speed is _____.<br> A. 0.02 m/s<br> B. 0.2 m/s<br> C. 2 m/s<br> D. 20 m/s
statuscvo [17]

<em>I am gonna have to say A 0.02  because 2 meters a second is way too fast 0.2 is a little more than reasonable and if 2 meters a second is too fast then 20 is off so</em> A. should be most reasonable

7 0
4 years ago
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