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dangina [55]
4 years ago
5

Ramon and sally are observing a toy car speed up as it goes around a circular track. ramon says, "the car's speeding up, so ther

e must be a net force parallel to the track." "i don't think so," replies sally. "it's moving in a circle, and that requires centripetal acceleration. the net force has to point to the center of the circle."
Physics
1 answer:
Anestetic [448]4 years ago
4 0
The changing speed demonstrates the nearness of an increasing speed; this centripetal quickening is of enduring with significance and coordinated in any regard cases toward the hub of the pivot. This increasing speed is, thus, created by utilizing a centripetal anxiety that is furthermore reliable in significance and coordinated toward the hub of revolution. contained in regards to revolution around a settled hub of a firm build that is not irrelevantly little in contrast with the span of the course, each and every molecule of the constitution portrays a uniform around activity with the equivalent rakish speed, yet with speed and increasing speed different with the range with comprehend to the hub.
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A rectangular field is to be enclosed on four sides with a fence. Fencing costs $2 per foot for two opposite sides, and $3 per f
borishaifa [10]
<h2>Dimension for cheap enclose = 32.45 ft x 23.52 ft</h2>

Explanation:

Area of rectangular field, A = 830 ft²

Length = l

Width = w

So we have

                 l x w = 830

                    l=\frac{830}{w}

Fencing costs $2 per foot for two opposite sides, and $3 per foot for the other two sides.

            Cost for fencing, C = 2 x 2 x w + 3 x 2 x l = 4 w + 6 l

             C=4w+6\times \frac{830}{w}

For minimum cost we have derivative is zero

           dC=4\times dw-6\times \frac{830}{w^2}\times dw\\\\0=4\times dw-6\times \frac{830}{w^2}\times dw\\\\w^2=1245\\\\w=32.45ft\\\\lw=830\\\\l\times 32.45=830\\\\l=23.52ft

Dimension for cheap enclose = 32.45 ft x 23.52 ft

8 0
3 years ago
A 5.22×104 kg railroad car moves on frictionless horizontal rails until it hits a horizontal spring stopper with a force constan
In-s [12.5K]

To solve this problem we will apply the principles of conservation of energy, for which we have to preserve the initial kinetic energy as elastic potential energy at the end of the movement. If said equality is maintained then we can affirm that,

\text{Initial Energy}=\text{Final Energy}

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Here,

m = mass

k = Spring constant

x = Displacement

v = Velocity

Rearranging to find the velocity,

mv^2 = kx^2

v^2 = \frac{kx^2}{m}

v = \sqrt{\frac{kx^2}{m}}

Our values are,

m = 5.22*10^4kg

k = 4.58*10^5N/m

x = 32cm = 0.32m

Replacing our values we have,

v = \sqrt{\frac{(4.58*10^5)(5.22*10^4)}{0.32}}

v = 2.733*10^5m/s

Therefore the velocity is 2.733*10^5m/s

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3 years ago
A primary coil of a transformer in a toy electric car has 300 turns and the secondary coil has 30 turns. How many volts will be
mel-nik [20]

Answer:

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Answer:

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