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3 years ago

..............................................

Physics

1 answer:

yarga [219]3 years ago

7 0

Answer:

Hi thx for points

Explanation:

Can you please mark as brainliest

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a student pushes a box with a total mass of 50kg. what is the net force on the box if it accelerates 1.5 m/s^2?

Zielflug [23.3K]

F=mass times acceleration so multiple 50 by 1.5 and u get 75

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3 years ago

Consider the f(x) = Acos(x) function shown in the figure in blue color. What is the value of amplitude A for this function?

Alex73 [517]

The amplitude of the red colored wave is 1 unit and the amplitude of the red colored wave is 2.1 unit.

<h3>What is amplitude of a wave?</h3>

The amplitude of a wave is the maximum displacement of the wave. It can also be described at the maximum upward displacement of a wave curve.

<h3>Amplitude of the red colored wave</h3>

From the graph, the amplitude of the red colored wave is 1 unit.

<h3>Amplitude of the blue colored wave</h3>

From the graph, the amplitude of the red colored wave is 2.1 unit.

Thus, the amplitude of the red colored wave is 1 unit and the amplitude of the red colored wave is 2.1 unit.

Learn more about amplitude here: brainly.com/question/3613222

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2 years ago

There's more to motion than simply changing position. True Or False

prohojiy [21]

Answer: I think that it is False, if its wrong I am sorry.

Explanation:

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3 years ago

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Two particles each of mass m and charge q are suspended by strings of length / from a common point. Find the angle e that each s

ozzi

Answer:

$\theta =\left (\frac{kq^{2}}{4L^{2}\times mg} \right )^{\frac{1}{3}}$

Explanation:

Let the length of the string is L.

Let T be the tension in the string.

Resolve the components of T.

As the charge q is in equilibrium.

T Sinθ = Fe ..... (1)

T Cosθ = mg .......(2)

Divide equation (1) by equation (2), we get

tan θ = Fe / mg

$tan\theta =\frac{\frac{kq^{2}}{AB^{2}}}{mg}$

$tan\theta =\frac{\frac{kq^{2}}{4L^{2}Sin^{\theta }}}}{mg}$

$tan\theta =\frac{kq^{2}}{4L^{2}Sin^{2}\theta \times mg}$

$tan\theta\times Sin^{2}\theta =\frac{kq^{2}}{4L^{2}\times mg}$

As θ is very small, so tanθ and Sinθ is equal to θ.

$\theta ^{3} =\frac{kq^{2}}{4L^{2}\times mg}$

$\theta =\left (\frac{kq^{2}}{4L^{2}\times mg} \right )^{\frac{1}{3}}$

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3 years ago

The swim bladder of a fish helps keep the fish from sinking by_______.

Slav-nsk [51]

Answer:

C. Increasing its buoyancy

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