The reaction is
the Q of reaction will be
Δ
Δ
Putting values
ΔG = -2068000 + (8.314)(298)lnQ
ΔG = -2068000 + (8.314)(298)ln(6350.66) = -2046305 J /mol = -2046.3 kJ / mol
Answer:
6. this is because atomic mass 11 - atomic number 5 is equal to 6 neutrons.
Answer:
0.6802 mol
Explanation:
1 grams K2S = 0.00907 mol
0.00907 x 75 = 0.6802 mol
Answer:
[AB] = 0.66M
Explanation:
rate = change in concentration/time
Initial concentration of AB = 1.5M
Let the concentration of AB after 10.3s be y
Therefore, rate = 1.5 - y/10.3
The rate equation is given as
rate = k[AB]^2 = 0.2y^2
0.2y^2 = 1.5 - y/10.3
2.06y^2 = 1.5 - y
2.06y^2 + y - 1.5 = 0
Using the quadratic formula
y = [-1 + or - √(1^2 -4×2.06×-1.5)/2(2.06)]
The value of y must be positive
y = (-1 + √13.36)/4.06 = -1+3.66/4.06 = 2.66/4.06 = 0.66
Concentration of AB after 10.3s is 0.66M
