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Temka [501]
3 years ago
5

Draw all the possible triacylglycerols that can be constructed from glycerol, palmitic acid, and oleic acid. rank them in order

of increasing melting point.

Chemistry
1 answer:
MrRissso [65]3 years ago
4 0
The structure of glycerol, palmitic acid and oleic acid is attached below. 

For the sake of simplicity, palmitic acid and oleic acid is abbreviated as 'O' and 'P', respectively. 

There are six different triacylglycerols can be constructed, from glycerol, palmitic acid, and oleic acid.

Qualitative structure of these triacylglycerols is represent in terms of 'P' and 'O'. 
                     OOO, OOP, OPO, PPO, POP, PPP 

Further, melting point of saturated fatty acid is greater as compared to unsaturated fatty acid. In present case, palmetic acid is saturated, while oleic acid is unsaturated (see structure below)

Thus, all possible triacylglycerols that can be constructed from glycerol, palmitic acid, and oleic acid, in order of increasing melting point are as follows:
                        OOO < OOP ≈ OPO < PPO ≈ POP < PPP  

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elixir [45]
There are 3 significant figures. Significant numbers are the numbers that build up your total number. 1-9 always count, 0 only counts if it’s after another number. For example: 0,901 has 3 significant numbers as does 0,910. 9,10 also has 3. 0,09 has just 1.
8 0
3 years ago
How many grams of N2 gas are present in 1.13 L of gas at 2.09 atm and 291 K?
solong [7]

Answer:

Mass= 2.77g

Explanation:

Applying

P=2.09atm, V= 1.13L, R= 0.082, T= 291K, Mm of N2= 28

PV=nRT

NB

Moles(n) = m/M

PV=m/M×RT

m= PVM/RT

Substitute and Simplify

m= (2.09×1.13×28)/(0.082×291)

m= 2.77g

6 0
3 years ago
Approximately how many elements are in the Periodic Table?
lakkis [162]
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7 0
3 years ago
Read 2 more answers
A 25.0 L gas cylinder at 32.0 is filled with 2.33 moles of carbon dioxide and 4.66 moles of nitrogen. Calculate the total pressu
Phantasy [73]

Answer:

P= 7.01 atm

P(CO₂)= 2.34 atm

Explanation:

Step 1: Convert the temperature to Kelvin

We will use the following expression.

K = °C + 273.15

K = 32.0°C + 273.15 = 305.2 K

Step 2: Calculate the total number of moles of the mixture

We will use the following expression.

n = nCO₂ + nN₂ = 2.33 mol + 4.66 mol = 6.99 mol

Step 3: Calculate the total pressure of the mixture

We will use the ideal gas equation.

P × V = n × R × T

P = n × R × T / V

P = 6.99 mol × 0.0821 atm.L/mol.K × 305.2 K / 25.0 L

P= 7.01 atm

Step 4: Calculate the partial pressure of carbon dioxide

We will use the ideal gas equation.

P(CO₂) × V = nCO₂ × R × T

P(CO₂) = nCO₂ × R × T / V

P(CO₂) = 2.33 mol × 0.0821 atm.L/mol.K × 305.2 K / 25.0 L

P(CO₂)= 2.34 atm

3 0
3 years ago
Formulate the sequence of steps needed to prepare 250.0 mL of a 0.005 M aqueous solution from solid KMnO4 and pure water.
S_A_V [24]

Answer:

Molarity is a unit that measures how much moles of solute dissolved in a liter of solvent. Molarity expressed using capital M while molarity, a different unit, expressed using lower case m.  

We want to make 0.005 M solution which means we need 0.005 moles of KmnO4 per liter of water. First, we have to calculate how many grams of KMnO4 we need for the solution.

We want to make 250ml solution, so the number of moles of KMnO4 we need will be:  0.005 mol/liter *(250 ml * 1liter/1000ml)= 0.005 mol/liter  * 1/4 liter = 0.00125 moles

The molecular mass of KMnO4 is 158g/mol, so the mass of KMnO4 we need will be:  0.00125 moles *  158g/mol=  0.1975 grams

We know that we need 0.1975 g of KMnO4, now we weigh them and put it inside a dish. After that, we prepare Erlenmeyer or a volumetric flask filled with water half of the volume needed(125ml). Pour the weighted solute into the flask, stir until all solute dissolved.

Then we add water to the container slowly until its volume reaches the 250ml mark.

3 0
3 years ago
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