Draw all the possible triacylglycerols that can be constructed from glycerol, palmitic acid, and oleic acid. rank them in order
of increasing melting point.
1 answer:
The structure of glycerol, palmitic acid and oleic acid is attached below.
For the sake of simplicity, palmitic acid and oleic acid is abbreviated as 'O' and 'P', respectively.
There are six different triacylglycerols can be constructed, from glycerol, palmitic acid, and oleic acid.
Qualitative structure of these triacylglycerols is represent in terms of 'P' and 'O'.
OOO, OOP, OPO, PPO, POP, PPP
Further, melting point of saturated fatty acid is greater as compared to unsaturated fatty acid. In present case, palmetic acid is saturated, while oleic acid is unsaturated (see structure below)
Thus, all possible triacylglycerols that can be constructed from glycerol, palmitic acid, and oleic acid, in order of increasing melting point are as follows:
OOO < OOP ≈ OPO < PPO ≈ POP < PPP
For the sake of simplicity, palmitic acid and oleic acid is abbreviated as 'O' and 'P', respectively.
There are six different triacylglycerols can be constructed, from glycerol, palmitic acid, and oleic acid.
Qualitative structure of these triacylglycerols is represent in terms of 'P' and 'O'.
OOO, OOP, OPO, PPO, POP, PPP
Further, melting point of saturated fatty acid is greater as compared to unsaturated fatty acid. In present case, palmetic acid is saturated, while oleic acid is unsaturated (see structure below)
Thus, all possible triacylglycerols that can be constructed from glycerol, palmitic acid, and oleic acid, in order of increasing melting point are as follows:
OOO < OOP ≈ OPO < PPO ≈ POP < PPP
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Answer:
Explanation:
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In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:
Thus, since we know the volume and concentration of the initial sample, we compute the resulting concentration as shown below:
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The mass of the copper cylinder is 177065.856g
Given:
Radius of the copper cylinder R=12cm
Height of the copper cylinder H=44cm
Density of the cylinder=8.90
To find:
Mass of the copper cylinder
<u>Step by Step by explanation:</u>
Solution:
According to the formula, Mass can be calculated as
and from this
Where, m=mass of the cylinder
=density of the cylinder
v=volume of the cylinder
And also cylinder is provided with radius and height value.
So volume of the cylinder is calculated as
Where =3.14
r=radius of the cylinder=12cm
h=height of the cylinder=44cm
Thus,
v=3.14 \times 144 \times 44
And we know that,
Substitute the known values in the above equation we get
m=177065.856g or 177.065kg
Result:
Thus the mass of the copper cylinder is 177065.856g