Answer:
ω = 3.66 rad/s
Explanation:
Given that
L= 1 m
M = 270 g = 0.27 kg
m = 3 g
u= 250 m/s
v= 140 m/s
We know that moment of inertia of the rod about it center
I=0.0225 kg.m²
The initial angular momentum
L₁ = m u r
Final angular momentum
L₂= I ω+m v r
Here r= L/4
r= 0.25 m
There is no any external torque ,it means that angular momentum will be conserve
L₁ = L₂
m u r = I ω+m v r
m r (u - v)=I ω
Now by putting the values
m r (u - v)=I ω
0.003 x 0.25 x (250- 140)=0.0225 x ω
ω = 3.66 rad/s
To solve this problem we will apply the concepts related to the double slit-experiment. Under this concept we understand the relationship between the minimum angle, depending on the order of the fringes, the wavelength and the distance between slits. Therefore we have the following relation,
Here,
m = Order of the fringes
D = Distance between slits
= Wavelength
Replacing with our values we have,
Through the relationship between distances then we have that the basic amplification distance is given by the relationship between the distance of the slit L and the angle, then
Thus the width of the central maximum is
Therefore the widht is 0.466m
<span>Neo and Morpheus's masses have gained a velocity (not equal to zero) which means their momentum is now based on gravity and friction alone.</span>
Answer:a device for calibrating thermometers at the boiling point of water at a known height above sea level or for estimating height above sea level by finding the temperature at which water boils.
Explanation: