Answer
given,
frequency from Police car= 1240 Hz
frequency of sound after return = 1275 Hz
Calculating the speed of the car = ?
Using Doppler's effect formula
Frequency received by the other car
..........(1)
u is the speed of sound = 340 m/s
v is the speed of the car
Frequency of the police car received
now, inserting the value of equation (1)
1.02822(340 - v) = 340 + v
2.02822 v = 340 x 0.028822
2.02822 v = 9.799
v = 4.83 m/s
hence, the speed of the car is equal to v = 4.83 m/s
Bob gained (80lbs x 14ft) = 1120 ft-lbs of energy.
Fred gained (110lbs x 14ft) = 1540 ft-lbs of energy
Since they both took the same amount of time, Fred's power (rate
of doing work) was greater than Bob's power (rate of doing work).
Answer:
13.18 m/s
Explanation:
Let the velocity of sports utility car is
-u as it is moving in opposite direction.
mc = 1200 kg, uc = 31.1 m/s
ms = 2830 kg, us = - u = ?
Using conservation of momentum
mc × uc + ms × us = 0
1200 × 31.1 - 2830 × u = 0
u = 13.18 m/s
Answer:
one could be magnet and another could be magnetic material
mark be brainliest
Answer:
B. Stages are continuous and gradual.
Explanation:
