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Zolol [24]
3 years ago
8

I have multiple questions!

Physics
1 answer:
UNO [17]3 years ago
3 0

I'm not sure about the rest but for question 2:

A theory is an attempt to come up with a big picture of all we know so far. It also drives future research as people do experiments to see if what the theory predicts actually happens. When experiments don’t support the theory, you have to change the theory and try again. That’s how science works. We come up with a “best guess” (theory), and then do research to test it’s accuracy. As we discover contradictions, we adjust the theory to take those into account, and then start testing the validity of the new theory.

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An object that’s
KonstantinChe [14]
An object thats NEGATIVELY charged has more electrons than protons, An object thats POSITIVELY charged has less electrons than protons, An object that NOT charged has the same number of electrons and protons.
5 0
3 years ago
Read 2 more answers
In a lab, a 5 L sample of gas with a pressure of 6 atm was transferred to a one liter flask.
wolverine [178]

Answer:

30 atm

Explanation:

P1V1 = P2V2

P2 = P1V1/V2

P2 = (6 atm * 5 L) / 1L

P2= 30 atm

6 0
3 years ago
Can the enzyme DNA polymerase be used to break down lactose
Lady_Fox [76]
Short answer: No

DNA polymerase is an enzyme responsible for copying DNA strands. Lactase is an enzyme responsible for breaking down lactose.
6 0
3 years ago
A river with a flow rate of 7 m3/s discharges into a lake with a volume of 9,000,000 m3. The concentration of a particular VOC i
soldi70 [24.7K]

Answer:

The concentration downstream reduces to 0.03463mg/L

Explanation:

Initially let us calculate the time it is required to fill the lake, since for that period of time the pollutant shall remain in the lake before being flushed out.

Thus the detention period is calculated as

t=\frac{V}{Q}\\\\t=\frac{9000000}{7}=1.285\times 10^{6}seconds\\\\\therefore t = 14.872days

Now the concentration of the pollutant after 14.872 days is calculated as

N_{t}=N_{0}e^{-kt}

where

N_{o} is the initial concentration

't' is the time elapsed after which the remaining concentration is calculated

k is the dissociation constant.

Applying values we get

N_{t}=3\times e^{-0.3\times 14.872}

N_{t}=0.03463mg/L

4 0
3 years ago
A +26.3 uC charge qy is repelled by a force
Musya8 [376]

Answer:

+1.46×10¯⁶ C

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = +26.3 μC = +26.3×10¯⁶ C

Force (F) = 0.615 N

Distance apart (r) = 0.750 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Charge 2 (q₂) =?

The value of the second charge can be obtained as follow:

F = Kq₁q₂ / r²

0.615 = 9×10⁹ × 26.3×10¯⁶ × q₂ / 0.750²

0.615 = 236700 × q₂ / 0.5625

Cross multiply

236700 × q₂ = 0.615 × 0.5625

Divide both side by 236700

q₂ = (0.615 × 0.5625) / 236700

q₂ = +1.46×10¯⁶ C

NOTE: The force between them is repulsive as stated from the question. This means that both charge has the same sign. Since the first charge has a positive sign, the second charge also has a positive sign. Thus, the value of the second charge is +1.46×10¯⁶ C

5 0
3 years ago
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