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babunello [35]
4 years ago
5

What are 5 different movements you can use to warm up

Physics
1 answer:
Artyom0805 [142]4 years ago
5 0

Answer:

1) Jumping Jacks (their a great way to get blood into your muscles and keep your blood running)

2) Toe touches (helps warm up your hamstring so you won‘t get injured easily)

3) Jog in place (Warm up leg muscles and whole body)

4) Arm circles (Warms up arm muscles)

5) 10,10,9,9. (This is something I like, you hop on 1 foot for 10 times and then switch to your other foot ten times without stopping, but after the ten you go back foryour previous hopping leg and hop 9 times this time and same for your other foot, THEN hop 8 times with the foot you started with and, keep going in that order in decending order until you reach 1, (a great way to warm up leg muscle)

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A plate falls vertically to the floor and breaks up into three pieces, which slide along the floor. immediately after the impact
pshichka [43]
Refer to the diagram shown below.

Define the (x,y) plane as the horizontal plane of the floor.
There was no momentum in the (x,y) plane before the plate hit the floor.

Let the velocity components in the (x) and (y) directions of the 100 g mass be Vx and Vy respectively, and that the resultant velocity, V, makes an angle θ below the negative x-axis as shown.

Because momentum is conserved, therefore
100*Vx + 320*2 = 0
100Vx = -640
Vx = -6.4 m/s

100Vy + 355*1.5 = 0
100Vy = -532.5
Vy = -5.325 m/s

V = √[(-6.4)² + (-5.325)²] = 8.33 m/s
θ = tan⁻¹ (-5.325/-6.4) = 39.8°

Answer:
The direction is 39.8° below the negative x-axis
The speed is 8.33 m/s


8 0
3 years ago
Read 2 more answers
If you observe an impaired driver, a safe behavior for you would be ____________.
timama [110]
Get someone else to drive me
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4 years ago
Describe why it was possible for a paperclip to ‘float’ on water
vesna_86 [32]

Answer:

because it weighs more than water

8 0
4 years ago
The Rite of Spring was composed by
7nadin3 [17]

The 'Rite of Spring' was composed by Igor Stravinsky.

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4 years ago
A 2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 V?What is the total energy stores in the
Rama09 [41]

1) 1.11\cdot 10^{-7} J

The capacitance of a parallel-plate capacitor is given by:

C=\frac{\epsilon_0 A}{d}

where

\epsilon_0 is the vacuum permittivity

A is the area of each plate

d is the distance between the plates

Here, the radius of each plate is

r=\frac{2.0 cm}{2}=1.0 cm=0.01 m

so the area is

A=\pi r^2 = \pi (0.01 m)^2=3.14\cdot 10^{-4} m^2

While the separation between the plates is

d=0.50 mm=5\cdot 10^{-4} m

So the capacitance is

C=\frac{(8.85\cdot 10^{-12} F/m)(3.14\cdot 10^{-4} m^2)}{5\cdot 10^{-4} m}=5.56\cdot 10^{-12} F

And now we can find the energy stored,which is given by:

U=\frac{1}{2}CV^2=\frac{1}{2}(5.56\cdot 10^{-12} F/m)(200 V)^2=1.11\cdot 10^{-7} J

2) 0.71 J/m^3

The magnitude of the electric field is given by

E=\frac{V}{d}=\frac{200 V}{5\cdot 10^{-4} m}=4\cdot 10^5 V/m

and the energy density of the electric field is given by

u=\frac{1}{2}\epsilon_0 E^2

and using

E=4\cdot 10^5 V/m, we find

u=\frac{1}{2}(8.85\cdot 10^{-12} F/m)(4\cdot 10^5 V/m)^2=0.71 J/m^3

7 0
4 years ago
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