Which best describes the trends in electronegativity on the periodic table? .

Chemistry

2 answers:

Vesna [10]4 years ago

6 0

The anwser should be c

Yuri [45]4 years ago

6 0

A. Electronegativity increases up and to the right.

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Which of the following solutions contains the largest number of moles of dissolved particles? a.) 25 ml of sodium chloride b.) 2

kirza4 [7]

Answer:

b.) 25 ml of aluminum hydroxide

Explanation:

For this question, we have to assume that we have the same concentration for all the solutions, for example, 1 M. Additionally, we have to take into account the ionization reaction for each species:

a) $NaCl~->~Na^+~+~Cl^-$ we have to ions

b) $Al(OH)_3~->~Al^+^3~+~3OH^-$ we have fourth ions

c) $CH_3COOH~->~CH_3COO^-~+~H^+$ we have two ions

d) $C_6H_1_2O_6~->~C_6H_1_2O_6$ we have one ion

If we have the same volume and the same concentration the variables that will help us to answer the question would be the number of ions. If we have more ions we will have more particles dissolved. Therefore the answer would be b) (due to the fourth ions).

I hope it helps

5 0

3 years ago

Read 2 more answers

What is the answer for number 2

Bond [772]

This answer is C hope this helped

5 0

3 years ago

Carbon-14 has a half-life of 5,700 years.

Maksim231197 [3]

Answer:

$3.106\ \text{g}$

Explanation:

$t_{1/2}$ = Half-life of carbon = 5700 years

t = Time at which the remaining mass is to be found = 10400 years

$m_0$ = Initial mass of carbon = 11 g

Decay constant is given by

$\lambda=\dfrac{\ln2}{t_{1/2}}$

Amount of mass remaining is given by

$m=m_0e^{-\lambda t}\\\Rightarrow m=m_0e^{-\dfrac{\ln2}{t_{1/2}} t}\\\Rightarrow m=11e^{-\dfrac{\ln 2}{5700}\times 10400}\\\Rightarrow m=3.106\ \text{g}$