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zavuch27 [327]
3 years ago
12

Carbon-14 has a half-life of 5,700 years.

Chemistry
1 answer:
Maksim231197 [3]3 years ago
5 0

Answer:

3.106\ \text{g}

Explanation:

t_{1/2} = Half-life of carbon = 5700 years

t = Time at which the remaining mass is to be found = 10400 years

m_0 = Initial mass of carbon = 11 g

Decay constant is given by

\lambda=\dfrac{\ln2}{t_{1/2}}

Amount of mass remaining is given by

m=m_0e^{-\lambda t}\\\Rightarrow m=m_0e^{-\dfrac{\ln2}{t_{1/2}} t}\\\Rightarrow m=11e^{-\dfrac{\ln 2}{5700}\times 10400}\\\Rightarrow m=3.106\ \text{g}

The amount of the substance that remains after 10400 years is 3.106\ \text{g}.

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What is the mass of 3.77mol of K3N?
AleksAgata [21]
<h3>Answer:</h3>

495 g K₃N

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.77 mol K₃N

<u>Step 2: Identify Conversions</u>

Molar Mass of K - 39.10 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of K₃N - 3(39.10) + 14.01 = 131.31 g/mol

<u>Step 3: Convert</u>

  1. Set up:                       \displaystyle 3.77 \ mol \ K_3N(\frac{131.31 \ g \ K_3N}{1 \ mol \ K_3N})
  2. Multiply/Divide:         \displaystyle 495.039 \ g \ K_3N

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

495.039 g K₃N ≈ 495 g K₃N

5 0
3 years ago
Chemical bonding for <br><br> Rb &amp; nitrogen,<br><br> Need help!!!
LekaFEV [45]
Covalent bonding!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
5 0
3 years ago
Before the development of electrophoresis to separate macromolecules, ____________ was used.
max2010maxim [7]

Before the development of electrophoresis to separate macromolecules, high-speed centrifugation was used to isolate DNA.

A laboratory procedure called electrophoresis is used to divide DNA, RNA, or protein molecules according to their size and electrical charge. The molecules are moved by an electric current through a gel or other matrix. The technology of electrophoresis is crucial for the separation and examination of nucleic acids. At the lab bench, cloned DNA fragments are frequently isolated and worked with using nucleic acid electrophoresis.

High-speed centrifugation employs centrifugal force to separate particles with various densities or masses suspended in a liquid. High-speed rotation of the solution inside the tube causes each particle's angular momentum to experience centrifugal forces inversely proportionate to its mass.

To know more about electrophoresis refer to: brainly.com/question/28709201

#SPJ4

4 0
1 year ago
Which elements above will form cations? List them below.
cricket20 [7]

Answer:

Halogens always form anions, alkali metals and alkaline earth metals always form cations. Most other metals form cations (e.g. iron, silver, nickel), whilst most other nonmetals typically form anions (e.g. oxygen, carbon, sulfur).

Explanation:

Examples: Sodium (Na+), Iron (Fe2+), Ammonium (NH4

7 0
3 years ago
If you are given a 0. 31 g piece of sodium metal to react with water, how many moles of hcl would it take to neutralize the sodi
Sphinxa [80]

The moles of HCl to neutralize the sodium hydroxide produced is<u> 0.0135 mole.  </u>

Neutralization or neutralization is a chemical response wherein an acid and a base react quantitatively with each other. In a reaction in water, neutralization outcomes in there being no excess of hydrogen or hydroxide ions gift in the answer.

<u>calculation:-</u>

<u />

2Na + 2H₂O  -----> 2NaOH + H₂

2 mol or 46g of Na produces 80 grams of NaOH

∴ 0.31 g of Na will produce = 80/46 × 0.31

                                              =  0.54 gram of NaOH.

mol of NaOH = 0.54/40

                      = 0.0135

Since both Hcl and NaOH have the same valance factor,

1 mole NaOH is needed to neutralize 1 mol HCl

∴ 0.0135 mole of NaOH will need = 0.0135 mole of HCl

mass = 0.0135 × 36.5

         =<u> 0.493 grams of HCL.</u>

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4 0
1 year ago
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