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torisob [31]
2 years ago
8

I really need the help, come on please, I got a Walmart gift CARD for anyone who can fill this out correctly

Chemistry
1 answer:
Taya2010 [7]2 years ago
6 0

Answer:

1) 1 Na3PO4 + 3 KOH  3 NaOH + 1 K3PO4

2) 1 MgF2 + 1 Li2CO3  1 MgCO3 + 2 LiF

3) 1 P4 + 3 O2  2 P2O3

4) 2 RbNO3 + 1 BeF2  1 Be(NO3)2 + 2 RbF

5) 2 AgNO3 + 1 Cu  1 Cu(NO3)2 + 2 Ag

6) 1 CF4 + 2 Br2  1 CBr4 + 2 F2

7) 2 HCN + 1 CuSO4  1 H2SO4 + 1 Cu(CN)2

Explanation:

8) 1 GaF3 + 3 Cs  3 CsF + 1 Ga

9) 1 BaS + 1 PtF2  1 BaF2 + 1 PtS

10) 1 N2 + 3 H2  2 NH3

11) 2 NaF + 1 Br2  2 NaBr + 1 F2

12) 1 Pb(OH)2 + 2 HCl  2 H2O + 1 PbCl2

13) 2 AlBr3 + 3 K2SO4  6 KBr + 1 Al2(SO4)3

14) 1 CH4 + 2 O2  1 CO2 + 2 H2O

15) 2 Na3PO4 + 3 CaCl2  6 NaCl + 1 Ca3(PO4)2

16) 2 K + 1 Cl2  2 KCl

17) 2 Al + 6 HCl  3 H2 + 2 AlCl3

18) 1 N2 + 3 F2  2 NF3

19) 1 SO2 + 2 Li2Se  1 SSe2 + 2 Li2O

20) 2 NH3 + 1 H2SO4  1 (NH4)2SO4

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Eric's father asked an engineer to survey the field behind their house. He wanted to plant some apple and pear trees there. Acco
Vsevolod [243]

Answer:

11,000 cm

Explanation:

Step 1: Given data

Width of the field (w): 17 meters

Length of the field (l): 38 meters

Step 2: Calculate the perimeter of the field

The field is a rectangle. We can find its perimeter (P) by adding its sides.

P = 2 × w + 2 × l = 2 × 17 m + 2 × 38 m = 110 m

Step 3: Convert the perimeter to centimeters

We will use the relationship 1 m = 100 cm.

110 m × (100 cm/1 m) = 11,000 cm

8 0
3 years ago
What is the molarity of a NaOH solution if 28.2 mL of a 0.355 M H2SO4 solution is required to neutralize a 25.0-mL sample of the
Verdich [7]

Answer:

[NaOH} = 0.4 M

Explanation:

In a reaction of neutralization, we determine the equivalence point of the titration. In this case, we have a strong base and a strong acid.

(H₂SO₄, is considered strong, but the first deprotonation is weak)

2NaOH  +  H₂SO₄  →  Na₂SO₄  + 2H₂O

As we have 2 protons in the acid, we need 2 OH⁻ from the base to form 2 molecules of water.

In the equivalence point we know mmoles of base = mmoles of acid

Let's finish the excersise with the formula

25 mL . M NaOH = 28.2 mL  .  0.355M

M NaOH = (28.2 mL  .  0.355M) / 25 mL → 0.400

8 0
3 years ago
Hydrates that have a low vapor pressure and remove moisture from air are said to be ___. Question 8 options: effloresce hygrosco
-Dominant- [34]

Answer:

Hygroscopic

Explanation:

An hygroscopic substance is one that absorbs moisture from the atmosphere and becomes wet. Their ability to remove water from air is less than that of deliquescent substances. Most of the solid hygroscopic substances forms pasty substances and not solutions like the deliquescent compounds.

Examples are sodium trioxonitrate(v), copper(ii) oxide e.t.c

Efflorescence compounds gives off their water of crystallization to the atmosphere.

4 0
2 years ago
Someone please help i don’t have much time left
REY [17]

Answer: Energy of reactants = 30, Energy of products = 10

Exothermic

Activation energy for forward reaction is 10.

Explanation:

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and \Delta H for the reaction comes out to be negative.

Energy of reactants = 30

Energy of products = 10

Thus as energy of the product < energy of the reactant, the reaction is exothermic.

Activation energy (E_a) is the extra energy that must be supplied to reactants in order to cross the energy barrier and thus convert to products.

E_a for forward reaction is (40-30) = 10.

6 0
3 years ago
Scientist can use trees to look at climates of the past. How? What information can they gather and how do they gather it? Explai
andrezito [222]

Explanation:

Scientist use trees a whole lot to look at climate of the past by examining tree rings.

These are layers of cambium in each successive years formed. They have an annual growth pattern and are known as tree rings.

Tree rings can be used to decipher the age of a tree.

  • These three rings can be used to interpret climatic patterns.
  • During a wet climate, the tree rings are more robust and bigger.
  • In a dry climate, the rings are thinner.
  • These alternating patterns can be used to decipher the climatic signatures in a tree.
  • Sometimes, it is possible to evaluate some certain isotopes that are useful in climatic studies.

learn more:

Climate change brainly.com/question/7824762

#learnwithBrainly

6 0
3 years ago
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