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o-na [289]
3 years ago
13

Calculate the number of atoms present in each following 2 mol fe

Chemistry
1 answer:
Nezavi [6.7K]3 years ago
7 0
Hope this helps you.

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The radius of a circle is 7.31. How should the circle area be reported?
Alona [7]

I'm not sure but it should be 7.31 times 2 times 3.14 or pi

7.31 x 2 x 3.14 = 45.9068

If you need to round to the nearest tenth it will be 45.9

If you need to round to the nearest hundredth it will be 45.91

7 0
3 years ago
Calculate the pH of a solution with an H+ ion concentration of 9.36 x 10-3 M ?
mel-nik [20]

Answer:

The answer is 2.03

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ {H}^{+} ]

where H+ is the Hydrogen ion concentration

From the question we have

pH =  -  log(9.36 \times  {10}^{ - 3} )  \\  = 2.02872415...

We have the final answer as

<h3>2.03 </h3>

Hope this helps you

6 0
2 years ago
2. State one difference between gas and vapour. Which of the following substance in the gaseous state should be called a vapour?
Neporo4naja [7]
Difference between Gas and Vapour:
                                                          
Gas:
        A thermodynamic state in which a substance exists only in one phase i.e. Gas phase. In above given examples N₂, He and CO₂ exists as gases at room temperature. These gases cannot form a solid or liquid phase along with gas phase as these states requires very low temperatures.

Vapours:
               It is a thermodyanamic state in which a substance exists in more than one phase. In given options Sulfur can exist in vapor state. This is because sulfur exists in a cyclic or chain form due to catenation (self linkage property). Therefore, a lower members of S allotrops can form a vapours.
3 0
3 years ago
The rate constant for a certain reaction is k = 5.40×10−3 s−1 . If the initial reactant concentration was 0.100 M, what will the
IceJOKER [234]

Answer : The concentration after 17.0 minutes will be, 4.05\times 10^{-4}M

Explanation :

The expression for first order reaction is:

[C_t]=[C_o]e^{-kt}

where,

[C_t] = concentration at time 't'  (final) = ?

[C_o] = concentration at time '0' (initial) = 0.100 M

k = rate constant = 5.40\times 10^{-3}s^{-1}

t = time = 17.0 min = 1020 s (1 min = 60 s)

Now put all the given values in the above expression, we get:

[C_t]=(0.100)\times e^{-(5.40\times 10^{-3})\times (1020)}

[C_t]=4.05\times 10^{-4}M

Thus, the concentration after 17.0 minutes will be, 4.05\times 10^{-4}M

4 0
3 years ago
The decomposition of ammonia is: 2 NH3(g) ⇌ N2(g) + 3 H2(g). If Kp is 1.5 × 103 at 400°C, what is the partial pressure of ammoni
ValentinkaMS [17]

Answer:

"6.7\times 10^{-4} \ atm" is the right answer.

Explanation:

Given:

Partial pressure of N_2,

= 0.20 atm

Partial pressure of H_2,

= 0.15 atm

K_p = 1.5\times 10^3 at 400^{\circ} C

As we know,

⇒ K_p = \frac{pN_2\times pH_2^3}{pNH_3^2}

By putting the values, we get

    1.5\times 10^3=\frac{0.20\times (0.15)^3}{pNH_3^2}

        pNH_3^2 = \frac{0.000675}{1.5\times 10^3}

                    =6.7\times 10^{-4} \ atm

                   

3 0
2 years ago
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