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o-na [289]
3 years ago
13

Calculate the number of atoms present in each following 2 mol fe

Chemistry
1 answer:
Nezavi [6.7K]3 years ago
7 0
Hope this helps you.

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Analyze: What pattern do you see? Make a rule: Based on your data, how are elements arranged into chemical families?
julia-pushkina [17]

Answer: in order of increasing atomic number.

Explanation: Elements in the same group have similar chemical properties. This is because they have the same number of outer electrons and the same valency.

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By replacing hardware safety features with software controls in the therac-25 machine, aecl was able to?
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Therac-25, AECL was able to reduce costs by replacing hardware safety features with software controls.

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5 0
2 years ago
Which describes Lithium chloride
Rasek [7]

Answer:

Lithium chloride is a white solid hygroscopic soluble in water.

8 0
2 years ago
The solubility of acetanilide in hot water (5.5 g/100 ml at 100∘C) is not very great, and its solubility in cold water (0.53 g/
Olin [163]

Answer:

89.4%

Explanation:

Initially, there is 5.0 of the acetanilide in 100 mL of water, then the solution is chilled at 0ºC. The solubility represents the amount that the solvent (water) can dissolve of the solute (acetanilide). So, at 0ºC, 100 mL of water can dissolve till 0.53 g of the compound, the rest will precipitate and will be recovered.

So, the mass that is recovered is 5.0 - 0.53 = 4.47 g

The percent recovery is:

(4.47/5)x100% = 89.4%

8 0
3 years ago
If a student mixes 75 mL of 1.30 M HNO3 and 150 mL of 6.5 M NaOH. is the final solution acidic, basic, or neutral
raketka [301]

Answer:

The solution is basic.

Explanation:

We can determine the nature of the solution via determining which has the large no. of millimoles (acid or base):

  • If no. of millimoles of acid > that of base; the solution is acidic.
  • If no. of millimoles of acid = that of base; the solution is neutral.
  • If no. of millimoles of acid < that of base; the solution is basic.

  • We need to calculate the no. of millimoles of acid and base:

no. of millimoles of acid (HNO₃) = MV = (1.3 M)(75.0 mL) = 97.5 mmol.

no. of millimoles of base (NaOH) = MV = (6.5 M)(150.0 mL) = 975.0 mmol.

<em>∴ The no. of millimoles of base (NaOH) is larger by 10 times than the acid (HNO₃).</em>

<em>So, the solution is: basic.</em>

4 0
2 years ago
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