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rosijanka [135]
3 years ago
13

How long does it take for a purple stem plant to grow

Chemistry
1 answer:
Gala2k [10]3 years ago
4 0
I couldn't really find anything about the growth time but it does say that it could remain viable in soil for up to 40 years

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Please help me with this or I may get an F in chemistry :(
umka21 [38]

Answer:

Subconscious - psychic activity just below the level of awareness

Election - the act of electing someone

Explanation:

I hope this helped enough, good luck in chemistry!

8 0
3 years ago
Classify HBr as a strong acid or a weak acid.<br><br><br> Strong Acid or Weak Acid?
IceJOKER [234]
HBr is a Strong acid
4 0
2 years ago
A compound is known to consist solely of carbon, hydrogen, and chlorine. Through elemental
OleMash [197]

Answer:

the empirical (lowest raios) is

C2H4Cl    

Explanation:

A compound is known to consist solely of carbon, hydrogen, and chlorine. Through elemental analysis, it was determined that the compound is composed of 24.27% carbon.

What is the empirical formula of this compound?

the compound has ONLY C, H, and Cl

the % Cl  = 100% - 24.27% -4.03% = 71.7%

in 100 gm, there are 71.7 gm Cl, 24.27 gm C, and 4.03 gm H

the number of moles are Cl=71.7/70.91 =1.01= ~ 1

                                          C = 24.27/12.0 = 2.02 =~ 2

                                           H = 403/1.01 = 3.97 =~   4

so   the empirical (lowest raios) is

C2H4Cl      

                                 

                               

3 0
3 years ago
Which is the right answer?
Talja [164]

Answer:

i think its C

Explanation:

3 0
3 years ago
A wooden artifact from an ancient tomb contains 60% of the carbon-14 that is present in living trees. How long ago was the artif
noname [10]

Answer:

The age of the sample is 4224 years.

Explanation:

Let the age of the sample be t years old.

Initial mass percentage of carbon-14 in an artifact = 100%

Initial mass of carbon-14 in an artifact = [A_o]

Final mass percentage of carbon-14 in an artifact t years = 60%

Final mass of carbon-14 in an artifact = [A]=0.06[A_o]

Half life of the carbon-14 = t_{1/2}=5730 years

k=\frac{0.693}{t_{1/2}}

[A]=[A_o]\times e^{-kt}

[A]=[A_o]\times e^{-\frac{0.693}{t_{1/2}}\times t}

0.60[A_o]=[A_o]\times e^{-\frac{0.693}{5730 year}\times t}

Solving for t:

t = 4223.71 years ≈ 4224 years

The age of the sample is 4224 years.

8 0
3 years ago
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