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svlad2 [7]
3 years ago
8

A cosmic ray electron moves at 7.65 ✕ 106 m/s perpendicular to the Earth's magnetic field at an altitude where field strength is

1.10 ✕ 10−5 T. What is the radius (in m) of the circular path the electron follows?
Physics
2 answers:
mariarad [96]3 years ago
8 0

Answer:

Radius = 3.96m

Explanation:

In a cyclotron motion, the radius of a charged particle path in a magnetic feild is given by:

r = mv/qB

Where r = radius

m = mass of particle= 9.1×10^-31kg

q = charged electron = 1.6×10^-19C

B = magnetic feid = 7.65×10^6T

V = velocity = 7.65×10^6

r = (9.1×10^-31)×(7.65×10^6) / (1.6×10^-19)(1.10 ×10^-5)

r = (6.9615×10^-24)/(1.76 ×10^-24)

r = 3.96m

diamong [38]3 years ago
3 0

Answer:

Explanation:

Force of a magnetic field, Fm = q × v × B

Centipetal force, Fa = (M × v^2)/r

Therefore, Fm = Fa

q × v × B = (M × v^2)/r

r = (m × v)/(q × B)

Where,

r = radius

m = mass of electron

= 9.1 × 10^-31 kg

q = electron charge

= 1.602 × 10^-19 C

B = magnetic field

= 1.10 ✕ 10^−5 T

v = velocity

= 7.65×10^6 m/s

r = (9.1 × 10^-31) × (7.65 × 10^6) / (1.6 × 10^-19) × (1.10 × 10^-5)

= 3.95 m

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If a snowboarder’s initial speed is 4 m/s and comes to rest when making it to the upper level. With a slightly greater initial s
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(a) At a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).

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<h3>Conservation of mechanical energy</h3>

The effect of height  and gravity on speed on the given planet Epislon is determined by applying the principle of conservation of mechanical energy as shown below;

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v² - u² = -2ghf

v² = u² - 2ghf

where;

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when u² = 2gh, then v² = 0,

when gravity reduces, u² > 2gh, and v² > 0

Thus, at a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).

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v² = u² - 2ghf

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  • u is the initial speed = 5 m/s
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Since g on Epislon is less than 9.8 m/s² of Earth;

5² - 2ghf > 3 m/s

Thus, if the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.

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Answer:

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Explanation:

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In order to find the electric flux we first have to find out the area of triangle.

Area of triangle = \frac{\sqrt{3} }{4} a^{2}

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Lets find electric flux,

      Electric Flux = E. A

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Now we can find the electric flux through each of the three sides.

Electric flux through three sides = \frac{7.046}{3}

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