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goldenfox [79]
3 years ago
12

What is the net force of an object with 6 N pushing on the left and 4 N pushing on the right?

Physics
2 answers:
VARVARA [1.3K]3 years ago
8 0

Answer:

i think its 2 n to the right

Karolina [17]3 years ago
7 0
The net force is 2N on the left :)
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You launch a cannonball at an angle of 35° and an initial velocity of 36 m/s (assume y = y₁=
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Approximately 4.2\; {\rm s} (assuming that the projectile was launched at angle of 35^{\circ} above the horizon.)

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The question assumed that there is no drag on this projectile. Additionally, the altitude of this projectile just before landing y_{1} is the same as the altitude y_{0} at which this projectile was launched: y_{0} = y_{1}.

Hence, the initial vertical velocity of this projectile would be the exact opposite of the vertical velocity of this projectile right before landing. Since the initial vertical velocity is 20.6\; {\rm m\cdot s^{-1}} (upwards,) the vertical velocity right before landing would be (-20.6\; {\rm m\cdot s^{-1}}) (downwards.) The change in vertical velocity is:

\begin{aligned}\Delta v_{y} &= (-20.6\; {\rm m\cdot s^{-1}}) - (20.6\; {\rm m\cdot s^{-1}}) \\ &= -41.2\; {\rm m\cdot s^{-1}}\end{aligned}.

Since there is no drag on this projectile, the vertical acceleration of this projectile would be g. In other words, a = g = -9.81\; {\rm m\cdot s^{-2}}.

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Hence, this projectile would be in the air for approximately 4.2\; {\rm s}.

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