How does reproduction leads to natural selection in a population

1 answer:

6 0

Natural selection requires variation between individuals. Mutations and reproduction increase genetic variation in a population. Natural selection occurs when environmental pressures favor certain traits that are passed on to offspring.

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The proton-proton chain ____ (A) combines two hydrogen nuclei to produce a single helium nucleus and energy.(B) splits a helium

emmainna [20.7K]

Answer:

(C) is the mechanism that increases the temperature between the photosphere and corona of the sun.

Explanation:

When a stars is converted from hydrogen to helium then this is known as proton -proton chain reaction.Due to this reaction the temperature between corona of the sun and photosphere increases.The main reason for increasing the temperature is exothermic reaction.

So the option C is correct.

(C) is the mechanism that increases the temperature between the photosphere and corona of the sun.

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4 years ago

What is matter in science

german

Matter in science is how much space you have.

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- Kayla <3

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3 years ago

Read 2 more answers

A solution may contain Ag+, Pb2+, and/or Hg22+. A white precipitate forms when 6 M HCl is added. The precipitate is partially so

omeli [17]

Answer:

All three are present

Explanation:

Addition of 6 M HCl would form precipitates of all the three cations, since the chlorides of these cations are insoluble: $AgCl (s), PbCl_2 (s), Hg_2Cl_2 (s)$ .

Firstly, the solid produced is partially soluble in hot water. Remember that out of all the three solids, lead(II) choride is the most soluble. It would easily completely dissolve in hot water. This is how we separate it from the remaining precipitate. Therefore, we know that we have lead(II) cations present, as the two remaining chlorides are insoluble even at high temperatures.
Secondly, addition of liquid ammonia would form a precipitate with silver: $AgCl (s) + 2 NH_3 (aq) + H_2O (l)\rightarrow [Ag(NH_3)_2]OH (s) + HCl (aq)$ ; Silver hydroxide at higher temperatures decomposes into black silver oxide: $2 [Ag(NH_3)_2]OH (s)\rightarrow Ag_2O (s) + H_2O (l) + 4 NH_3 (g)$ .
Thirdly, we also know we have $Hg_2^{2+}$ in the mixture, since addition of potassium chromate produces a yellow precipitate: $Hg_2^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow Hg_2CrO_4 (s)$ . The latter precipitate is yellow.