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Dovator [93]
3 years ago
12

Longshore drift occurs when: the repetitive action of swash and backwash transports sediment sideways along the coas powerful wa

ves wash against the shore, carrying rock and sand away rock particles in waves grind against the shore none of the above
Chemistry
2 answers:
Mashcka [7]3 years ago
6 0
<span>Longshore drift is a geographical process that consists of the transportation of sediments (clay, silt, sand and shingle) along a coast at an angle to the shoreline, which is dependent on prevailing wind direction, swash and backwash. This process occurs in the littoral zone, and in or close to the surf zone.</span>
9966 [12]3 years ago
4 0

Answer is: repetitive action of swash and backwash transports sediment sideways along the coast.

Longshore drift is a geological process of the transportation of sediments.

Wind squeezes water along the coast and generates a water current which moves parallel to the coast.

Longshore drift plays a large role in the evolution of a shoreline.

There are formulations (Bijker formula, The Van Rijn formula ...) that explain intensity of longshore drift.

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What is a positive effect of nuclear power plants?
vagabundo [1.1K]

Answer:

MRCORRECT has answered the question

Explanation:

Nuclear Energy Pros and Cons

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4 years ago
Find the Molarity of a solution containing 2.5 moles of solute in 15000 milliliters.
garri49 [273]
Molarity is defined by the number of moles of a substance dissolved in a number of liters in solution. 15,000 milliliters is equal to 15 liters, so

2.5/15 = 0.1666... M

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3 years ago
Write a balanced molecular reaction for the hydrogenation of ethyne to the saturated alkane.
vredina [299]

Explanation:

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C2H2 + 2H2 => C2H6.

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3 0
3 years ago
Many drugs are sold as their hydrochloric salts (R2NH2+Cl−), formed by reaction of an amine (R2NH) with HCl. Part 1 out of 4 Dra
Drupady [299]

Answer:

Hi

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Download docx
4 0
3 years ago
A 150 mL of oxygen gas is collected over water at 20 °C and 758 torr. What volume will the same sample of oxygen occupy at STP w
Stella [2.4K]

Answer:

The volume would be; 136.17 ml

Explanation:

Volume V1 = 150 mL

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At STP;

Volume V2 = ?

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Using the general gas equation;

P1V1 / T1   = P2V2 / T2

Making V2 subject of formulae;

V2 = P1V1T2 / T1P2

Inserting the values we have;

V2 = 740.46 * 150 * 273  /  293 * 760

V2 = 136.17 ml

3 0
3 years ago
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