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ruslelena [56]
3 years ago
6

Just the equation with the steps please

Mathematics
2 answers:
Sholpan [36]3 years ago
7 0

28000 + 3000x = 36000 + 2000x

Subtract 2000x from both sides: 28000 + 1000x = 36000

Subtract 28000 from both sides: 1000x = 8000

Divide both sides by 1000: x = 8.

Let me know if there is more to the problem!

Vedmedyk [2.9K]3 years ago
5 0

28,000+3,000=31,000+2000=33000


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Solve 6 and 7 please?
Charra [1.4K]

Hey!

---------------------------------------------------------------------

We know that (a = -3), (b = 2), (c = 5), and (d = -4)

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Question 6:

= 5ac - 2b

= 5(-3)(5) - 2(2)

= 5(-15) - 4

= -75 - 4

<u>= -79</u>

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Question 7:

= ab/d

= (-3)(2)/-4

= -6/-4

<u>= 1 1/2</u>

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Hope this helped, good luck!

6 0
3 years ago
Will the product be greater or less then each factor? 56.9×2.01
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Write an equation for the ordered pairs (0,5) (1,0)
Phoenix [80]
M=0-5/1-0
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7 0
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If I ride a bicycle at a rate of 5m/s,how long will it take me to ride a distance of 12km at the same rate?​
Travka [436]

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3 0
3 years ago
Kevin cuts lawns during the summer months. He charges $10 plus $5 per hour. The algebraic model is C = 5h + 10, where C represen
Oxana [17]

Answer:

\begin{center}\begin{tabular}{ c c c }Hours(h) & Total Cost(C) \\ 1 & 15  \\  2 & 20  \\   3 & 25  \\ 4 & 30   \\ 5 & 35    \end{tabular}\end{center}

Step-by-step explanation:

Given that:

Kevin charges $10 plus $5 per hours

C = 5h + 10

To find:

The table of values for hours worked from 1 to 5.

Solution:

First of all, let us put h = 1 in the given equation:

C = 5 \times 1 + 10

C = 5 + 10 = $15

Now, let us put h = 2 in the given equation:

C = 5 \times 2 + 10

C = 10 + 10 = $20

Now, let us put h = 3 in the given equation:

C = 5 \times 3 + 10

C = 15 + 10 = $25

Now, let us put h = 4 in the given equation:

C = 5 \times 4 + 10

C = 20 + 10 = $30

Now, let us put h = 5 in the given equation:

C = 5 \times 5 + 10

C = 25 + 10 = $35

So, the table becomes each row incrementing h by 1:

\begin{center}\begin{tabular}{ c c c }Hours(h) & Total Cost(C) \\ 1 & 15  \\  2 & 20  \\   3 & 25  \\ 4 & 30   \\ 5 & 35    \end{tabular}\end{center}

8 0
3 years ago
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