Answer:
Explanation:
Given
mass of children
distance between two children
suppose small child is at a distance of x m from pivot point
so torque of small child and heavier child must be equal
how much does a bookshelf weigh if the movers are pushing it at a speed of 10 m/s^2 by applying 100 N force
1 answer:
Answer:
10 kg
Explanation:
Assuming a frictionless surface, then force F=ma where F is the applied force, m is the mass and a is acceleration. Making m the subject of the formula then
Substituting 100 N for the applied force F and 10 m/s^2 for acceleration a then the value of m will be
Therefore, in terms of kilograms, the bookshelf weighs 10 Kg
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Answer:
10.01 cm
Explanation:
Given that,
The time delay between transmission and the arrival of the reflected wave of a signal using ultrasound traveling through a piece of fat tissue was 0.13 ms.
The average propagation speed for sound in body tissue is 1540 m/s.
We need to find the depth when the reflection occur. We know that, the distance is double when transmitting and arriving. So,
or
d = 10.01 cm
So, the reflection will occur at 10.01 cm.