Light because it is an electromagnetic wave and they can travel through the vacuum in outer space.
Answer:
The magnitude of the electric field in the second case will be
of the electric field in the first case
Explanation:
The electric field at a distance
< R from the center of the sphere is given by
the formula
=
where R is the radius of the sphere, and, Q is the charge uniformly distributed on the sphere.
It is given that the same charge Q is distributed uniformly throughout a sphere of radius 2R and we have to find the electric field at same distance
from the center.
In the second case the electric field will be given by
= 
Therefore the magnitude of the electric field in the second case will be
of the electric field in the first case.
Answer:
6.37 x 10⁷Hz
Explanation:
Given parameters:
Wavelength = 4.71m
Unknown:
Frequency = ?
Solution:
To solve this problem, we use the expression below:
V = F∧
V is the velocity = 3 x 10⁸m/s
F is the frequency
∧ is the wavelength
3 x 10⁸ = F x 4.71
F = 63694267.52Hz = 6.37 x 10⁷Hz
-- If it's all happening horizontally, then gravity is not involved.
Only the spring is.
-- If there's no friction, then total energy is conserved.
-- If you put 190J of energy into the spring by moving the mass,
and there's only 55J of potential energy in the spring now, then
the other 135J of energy is in the kinetic energy of the mass and
the moving parts of the spring.