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rewona [7]
3 years ago
13

A potter's wheel moves uniformly from rest to an angular speed of 0.20 rev/s in 32.0 s. (a) Find its angular acceleration in rad

ians per second per second. rad/s2 (b) Would doubling the angular acceleration during the given period have doubled final angular speed?
Physics
1 answer:
Kay [80]3 years ago
3 0

a. The wheel accelerates uniformly, so its constant acceleration is equal to the average acceleration:

\alpha=\dfrac{0.20\frac{\rm rev}{\rm s}-0}{32.0\,\rm s}=0.0063\dfrac{\rm rev}{\mathrm s^2}

b. Yes. Since

\alpha=\dfrac{\Delta\omega}{\Delta t}=\dfrac\omega{\Delta t}

then multiplying \alpha by 2 means we double the change in angular speed, but the wheel starts from rest so only the final angular speed \omega gets doubled.

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