Question

A student collects 450. mL of HCl gas at a pressure of 101 kPa and a temperature of 17ºC. What would the volume of the gas be if the temperature was increased to 25ºC and the pressure was increased to 104 kPa?

Answer 1

Answer:

449 mL

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,  

V₁ = 450 mL

V₂ = ?

P₁ = 101 kPa

P₂ = 104 kPa

T₁ = 17 ºC

T₂ = 25 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (17 + 273.15) K = 290.15 K

T₂ = (25 + 273.15) K = 298.15 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac {{101}\times {450}}{290.15}=\frac {{104}\times {V_2}}{298.15}$

Solving for V₂ , we get:

V₂ = 449 mL