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3 years ago

When can a compound be treated like an element when balancing chemical equations?

2 answers:

7 0

A compound can be treated like an element when balancing chemical equations when : A. when there is no change to the atoms in the compound

If they remain together during the reaction, you can treat a compound as a singe atom.

hope this helps

yuradex [85]3 years ago

4 0

Answer: Option (A) is the correct answer.

Explanation:

When two or more elements combine chemically to each other then it results in the formation of a substance known as a compound.

On the other hand, a substance that contains same atoms is known as an element.

For example, $F_{2}$ is a diatomic molecule and since it contains more than one atom so it is a compound also.

Therefore, we can conclude that when there is no change to the atoms in the compound then a compound can be treated like an element when balancing chemical equations.

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Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el

Dovator [93]

Answer: 406 hours

Explanation:

$Q=I\times t$

where Q= quantity of electricity in coloumbs

I = current in amperes = 39.5 A

t= time in seconds = ?

The deposition of copper at cathode is represented by:

$Cu^{2+}+2e^-\rightarrow Cu$

$96500\times 2=193000$ Coloumb of electricity deposits 1 mole of copper

i.e. 63.5 g of copper is deposited by = 193000 Coloumb

Thus 19.0 kg or 19000 g of copper is deposited by = $\frac{193000}{63.5}\times 19000=57748032$ Coloumb

$57748032=39.5\times t$

$t=1461975sec=406hours$ (1hour=3600s)

Thus it will take 406 hours to plate 19.0 kg of copper onto the cathode if the current passed through the cell is held constant at 39.5 A

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3 years ago

4 examples of Substances that sublime?

AVprozaik [17]

1. Dry Ice (solid carbon dioxide)

2. Iodine

3. Arsenic

4. Naphthalene

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4 years ago

A tank contains 90 kg of salt and 2000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain

sashaice [31]

Answer:

a) 90 kg

b) 68.4 kg

c) 0 kg/L

Explanation:

Mass balance:

$-w=\frac{dm}{dt}$

w is the mass flow

m is the mass of salt

$-v*C=\frac{dm}{dt}$

v is the volume flow

C is the concentration

$C=\frac{m}{V+(6-3)*L/min*t}$

$-v*\frac{m}{V+(6-3)*L/min*t}=\frac{dm}{dt}$

$-3*L/min*\frac{m}{2000L+(3)*L/min*t}=\frac{dm}{dt}$

$-3*L/min*\frac{dt}{2000L+(3)*L/min*t}=\frac{dm}{m}$

$-3*L/min*\int_{0}^{t}\frac{dt}{2000L+(3)*L/min*t}=\int_{90kg}^{m}\frac{dm}{m}$

$-[ln(2000L+3*L/min*t)-ln(2000L)]=ln(m)-ln(90kg)$

$-ln[(2000L+3*L/min*t)/2000L]=ln(m/90kg)$

$m=90kg*[2000L/(2000L+3*L/min*t)]$

a) Initially: t=0

$m=90kg*[2000L/(2000L+3*L/min*0)]=90kg$

b) t=210 min (3.5 hr)

$m=90kg*[2000L/(2000L+3*L/min*210min)]=68.4kg$

c) If time trends to infinity the division trends to 0 and, therefore, m trends to 0. So, the concentration at infinit time is 0 kg/L.

6 0

3 years ago

The mass of Jupiter is 300 times the mass of the earth. Jupiter orbits the sun with Jupiter = 11.9 yr in an orbit with Jupiter =

kondaur [170]

The orbital period is proportional to r^(3/2) and does not depend on the satellite's mass. Any object at Jupiter's position will have the same orbital period regardless of mass. The correct answer is 11.9 yr. <u>Option C.</u>

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The momentum of this throw being greater the Earth's orbit would have been more elliptical or it might have been completely ejected from the solar system forever. The Earth's orbit defines a two-dimensional plane called the Ecliptic. It takes about 365 days for the earth to revolve around the sun. After years of analysis, Kepler found that Mars' orbit was likely elliptical, with the Sun at one of his focal points of the ellipse. This led Kepler to discover that all planets orbit the Sun in elliptical orbits and that the Sun is at one of his two focal points.

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1 year ago

When methane is burned with oxygen, the products are carbon dioxide and water. if you produce 9 grams of water and 11 grams of c

Alina [70]

4 grams of methane is <span>burned with oxygen,. Hope this helped</span>

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