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Softa [21]
3 years ago
11

Need help please help

Mathematics
1 answer:
Vesna [10]3 years ago
6 0
The vertex is (105,7)

Notice how on the graph, the y value peaks at 7. The y values to the left and right are symmetrical, meaning that the x value for the y value of 7 is the axis of symmetry, and the point (105,7) is the vertex.
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Write equivalent fractions for 1 2/3 and 1 7/8 using 24 as the common denominator 2 24 7 1 0​
NARA [144]

<u>Answer:</u>

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2×8=16

7×3=21

2/3 + 7/8 = 16/24 + 21/24

7 0
3 years ago
What is the value of<br> x 2 - 14 when x = 9?
Nonamiya [84]

Answer:

4.

Step-by-step explanation:

9(2) = 18

18-14=4

5 0
3 years ago
Read 2 more answers
Find the missing value so that the two points have a slope of 2/7. (-1, -1) and (x, 1)
mihalych1998 [28]
What you do is just find the missing value of the x.
4 0
3 years ago
f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2
iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4,\infty)

g(x)=2x^2+8x+6=2(x^2+4x+3)

g(x)=0

2(x^2+4x+3)=0

x^2+4x+3=0

x^2+3x+x+3=0

x(x+3)+1(x+3)=0

(x+1)(x+3)=0

x+1=0\implies x=-1

x+3=0\implies x=-3

Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2

g(x)=2(x^2+4x)+6

g(x)=2(x^2+2\times x\times 2+4-4)+6=2(x^2+2\times x\times 2+4)-8+6

g(x)=2(x+2)^2-2

By comparing with the equation of parabola

y=a(x-h)^2+k

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2,\infty)

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

3 0
3 years ago
Yo if u need an bralest i got chu
dybincka [34]

Answer:

PLease

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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