Answer:
pH = 14 - pH = 14 - 1 = 13
Explanation:
0.05M Ca(OH)₂ => 0.05M Ca⁺(aq) + 2(0.05M) OH⁻(aq)
pOH = -log[OH⁻] = -log(0.100) = 1
pH = 14 - pH = 14 - 1 = 13
Answer:
You need the mass of Mg and Ca in the sample and their molar masses
Explanation:
Its the only answer that made sense because using those 4, can give you their ration
The volume in liters of 85.5 grams of carbon monoxide at STP would be —— 68.4L
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