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tigry1 [53]
2 years ago
13

8. Rewrite each of the following as an "ordinary” decimal

Chemistry
1 answer:
saveliy_v [14]2 years ago
3 0

Answer:

????????

Explanation:

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WHAT MEASURING EQUIPMENT DID LEANNE USE TO GET HER RESULTS
julia-pushkina [17]

Answer:

Thietbi  od

Explanation:

7 0
2 years ago
Read 2 more answers
Acetone, a common solvent, has density 0.79g/cm3 at 20 degrees celcius. What is the volume of 85.1g of acetone at 20 degrees cel
RoseWind [281]
1)

a)

D = 0.79 g/cm³           m = 85.1 g

D = m / V

0.79 = 85.1 / V

V = 85.1 / 0.79 => 107.72 cm³
____________________________________________
b) D = m / V

0.79 = m / 125

m = 0.79 x 125 => 98.75 g
____________________________________________

hope this helps!

4 0
2 years ago
Read 2 more answers
When there are more electrons than protons an object has an overall<br> charge.
azamat

Answer:it would have a negative charge because  electrons are negative

Explanation:

7 0
3 years ago
A salt forms in the reaction of barium with chlorine. What is the most likely formula unit of this salt?
Scrat [10]
The answer to this question would be: BaCl 2
Barium is an alkali metal with 56 atomic number. Barium located in the group 2 of the periodic table because it has 2 valence electrons. Chlorine is a nonmetal that has 1 valence electron. When react, it would need 2 chlorine for each barium as the valence electron of barium is twice the chlorine. 
6 0
2 years ago
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If you collect 1.75 L of hydrogen gas during a lab experiment when the room temperature is 23oC and the barometric pressure is 1
ziro4ka [17]

Answer:

n=0.0747mol

Explanation:

Hello,

In this case, since we can consider hydrogen gas as an ideal gas, we check the volume-pressure-temperature-mole relationship by using the ideal gas equation:

PV=nRT

Whereas we are asked to compute the moles given the temperature in Kelvins, thr pressure in atm and volume in L as shown below:

n=\frac{105kPa*\frac{0.009869atm}{1kPa}*1.75L}{0.082\frac{atm*L}{mol*K}*(23+273.15)K} \\\\n=0.0747mol

Best regards.

8 0
2 years ago
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