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Volgvan
3 years ago
14

In order for a nonmetal to obey the octet rule, it____.

Chemistry
2 answers:
lyudmila [28]3 years ago
6 0

Answer: Option (C) is the correct answer.

Explanation:

Non-metals are the species which have deficiency of electrons. Therefore, in order to gain stability non-metals tend to gain electrons so that their octet gets completely filled.

For example, atomic number of chlorine is 17 and its electrons are distributed as 2, 8, 7. Thus, in order to completely filled the shell chlorine will gain one electron from an electron rich atom or metal.

Hence, we can conclude that in order for a nonmetal to obey the octet rule, it gains electrons.

lubasha [3.4K]3 years ago
3 0
<span>C. In order for a nonmetal to obey the octet rule, it gains electrons.</span>
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Is it the power of material evidence that wins, not the authority of experts that
kvasek [131]

Yes, it is the power of material evidence that wins.

  • Evidence used to support or refute a scientific theory or hypothesis is known as material evidence.
  • Evidence is also used by scientists in various contexts, such as when they apply ideas to real-world issues.
  • Whether a person accepts the data as proof depends on their presumptions or views regarding how observations relate to a theory.
  • A creative hypothesis is developed by a scientist and may be refuted by testing it against evidence or established truths.
  • Evidence can refute a hypothesis by demonstrating facts that are at odds with it. In contrast, the presence of evidence does not preclude the possibility of future, undiscovered evidence supporting the idea.

Therefore, it is the power of material evidence that wins, not the authority of experts that

proves an answer in Science.

Learn more about hypothesis here: brainly.com/question/606806

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7 0
2 years ago
The gas in a closed container has a pressure of 3.00 x 10² kPa 30 ° C. What will the pressure be if the temperature is lowered t
Rainbow [258]

Answer: 100kPa

Explanation:

P1 = 3.00 x 10² kPa , P2 =?

T1 = 30°C = 30 +273 = 303k

T2 = —172°C = —172 + 273 = 101k

P1/T1 = P2/T2

3 x 10² / 303 = P2 / 101

P2 = (3 x 10² / 303) x 101

P2 = 100kPa

6 0
3 years ago
What is the name of the ionic compound RbCI?
zloy xaker [14]

Answer:A

Explanation:taking the test now

5 0
4 years ago
The complete orbital notation diagram of an atom is shown.
Yuki888 [10]

Answer:

Explanation:

From the description provided by the statement of the problem, we can easily solve for the values of the angular momentum quantum number.

Let us represent the atom as J:

In atom J, we have five sub-orbitals in which there 9 electrons. From the designation used to represent sublevels, we can write the notation as below:

             J = 10 electrons = 1s² 2s² 2p⁵

The s-sublevel can only contain 2 electrons

p-sublevel can contain 6 electrons but we have just 5 electrons in there.

Now, to find the angular momentum quantum number, we need to understand what this quantum number denotes.

This quantum number is also known as azimuthal or secondary quantum number. It gives the shape of the orbitals in subshells accomodating electrons. This quantum number is designated by (l).

         l (n-1)            name of orbital               shape of orbital

             0                     s                                   spherical

             1                     p                                    dumb-bell

             2                    d                                    double dumb-bell

             3                    f                                      complex

J  = 1s² 2s² 2p⁵

where 1 and 2 coefficients are the principal quantum numbers(n).

            s and p are the shape of the orbitals

For 1s², the l vaue is 0 because the electron is in the s orbital

     2s² the l value is 0, 1 and the electron can be in the s or p orbitals

     2p⁵ the l value is 0, 1 and the electrons can be in the s or p orbitals

The quantum number gives the shape of the orbital.

8 0
3 years ago
A compound is 7.74% hydrogen and 92.26% carbon by mass. At 100°C a 0.6883 g sample of the gas occupies 250 mL when the pressure
ycow [4]

<u>Answer:</u> The molecular formula for the compound is C_6H_6

<u>Explanation:</u>

We are given:

Percentage of C = 92.26 %

Percentage of H = 7.74 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 92.26 g

Mass of H = 7.74 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{92.26g}{12g/mole}=7.68moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{7.74g}{1g/mole}=7.74moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 7.68 moles.

For Carbon = \frac{7.68}{7.68}=1

For Hydrogen = \frac{7.74}{7.68}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 1

The empirical formula for the given compound is CH

  • <u>Calculating the molar mass of the compound:</u>

To calculate the molecular mass, we use the equation given by ideal gas equation:

PV = nRT

Or,

PV=\frac{m}{M}RT

where,

P = pressure of the gas = 820 torr

V = Volume of gas = 250 mL = 0.250 L  (Conversion factor:  1 L = 1000 mL )

m = mass of gas = 0.6883 g

M = Molar mass of gas = ?

R = Gas constant = 62.3637\text{ L. torr }mol^{-1}K^{-1}

T = temperature of the gas = 100^oC=(100+273)K=373K

Putting values in above equation, we get:

820torr\times 0.250L=\frac{0.6883g}{M}\times 62.3637\text{ L torr }mol^{-1}K^{-1}\times 373K\\\\M=\frac{0.6883\times 62.3637\times 373}{820\times 0.250}=78.10g/mol

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 78.10 g/mol

Mass of empirical formula = 13 g/mol

Putting values in above equation, we get:

n=\frac{78.10g/mol}{13g/mol}=6

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(1\times 6)}H_{(1\times 6)}=C_6H_6

Hence, the molecular formula for the compound is C_6H_6

8 0
3 years ago
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