Answer:
<em>C</em> H2SO4 = 9.79 M
Explanation:
- molarity (M) ≡ # dissolved species / V sln
- H2SO4 ↔ H3O+ + SO4-
∴ %w/w H2SO4 = 960% = g H2SO4 / g sln * 100
⇒ 9.6 = g H2SO4 / g sln
calculation base: 1000 g sln
⇒ g H2SO4 = 9600g
⇒<em> </em>mol<em> </em>H2SO4 =<em> </em>9600 g H2SO4 * ( mol H2SO4/ 980g H2SO4 ) = 9.796 mol H2SO4
⇒ V sln = 1000g sln / 1000g/L = 1 L sln
∴ ρ H20 ≅ 1000 Kg/m³ = 1000 g/L
⇒ <em>C</em> H2SO4 = 9.796 mol H2SO4 / 1 L sln
⇒ <em>C</em> H2SO4 = 9.796 M
3.65. The mole ratio from the balanced equation is 2 moles CO2 : 2 moles CO. 2.
Answer:
the answer to the answer above is motion
Answer:
1:is option A as it have OH- group (base)
2:a),antacid as it's weak base
In the reaction of water, 2H2 is oxidized to form 2H2O by gaining oxygen atom which shows that 2H2 is reducing agent as it undergoes oxidation.
<h3>What is reducing agent?</h3>
A reducing agent is a type of chemical that "donates" an electron to another atom that needs an electron. This type of reaction in which loss of electron occurs is called reduction reaction.
So we can conclude that 2H2 is oxidized to form 2H2O by gaining oxygen atom which shows that 2H2 is reducing agent as it undergoes oxidation.
Learn more about reduction here: brainly.com/question/3457976
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