The concentration required to begin to precipitate PbCl2 for PbCl2 is 0.0216 M.
<h3>
What is molarity?</h3>
Molarity is the measure of the concentration of any solute in per unit volume of the solution.
The reaction is 
The molarity of lead is 0.025 M
The ksp is given 17×10⁻⁵
Now, calculating the concentration
![[Pb^2^+] = 0.025 M.\\Ksp = 1.17 \times 10^-^5\\Ksp = [Pb^2^+] \times [Cl^-]^2\\[Cl^-] = \dfrac{\sqrt{ Ksp}}{[Pb^2^+]} \\\\[Cl^-] = \dfrac{\sqrt{ 0.0000117}}{0.025} \\[Cl^-] = 2.16 \times 10^-^2M.](https://tex.z-dn.net/?f=%5BPb%5E2%5E%2B%5D%20%3D%200.025%20M.%5C%5CKsp%20%3D%201.17%20%5Ctimes%2010%5E-%5E5%5C%5CKsp%20%3D%20%5BPb%5E2%5E%2B%5D%20%5Ctimes%20%20%5BCl%5E-%5D%5E2%5C%5C%5BCl%5E-%5D%20%3D%20%20%5Cdfrac%7B%5Csqrt%7B%20Ksp%7D%7D%7B%5BPb%5E2%5E%2B%5D%7D%20%5C%5C%5C%5C%5BCl%5E-%5D%20%3D%20%20%5Cdfrac%7B%5Csqrt%7B%200.0000117%7D%7D%7B0.025%7D%20%20%5C%5C%5BCl%5E-%5D%20%3D%202.16%20%5Ctimes%2010%5E-%5E2M.)
Thus, the concentration required to begin to precipitate PbCl2 for PbCl2 is 0.0216 M.
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Answer:
A series circuit is defined as the circuit in which a number of resistances are connected one after the other.. In a series circuit, the flow of current follows a single path.
A parallel circuit is defined as the circuit in which a number of resistances are linked across each other in such a way that one terminal of each resistance is connected to form a junction point while the remaining end is also connected to form another point.
You havent added the diagram so i cant tell you the answer, but i added the definition of each circuit, see if that helps!
Number of moles ( n ) = ?
Volume ( V ) = 0.25 L
Molarity of solution ( M ) = 2.00 M
n = M x V
n = 2.00 x 0.25
n = 0.5 moles of Ba(NO₃)₂
hope this helps!
Answer:
<u>Grammar</u> is the rules for speaking or writing a language.
Chemical bonds have been broken down and new substances have been formed. Hope this helps.
