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Arte-miy333 [17]
2 years ago
7

HELP please. Only if your POSITIVE

Chemistry
1 answer:
tatuchka [14]2 years ago
7 0

Answer:

B.

Explanation:

The two reactions shown in the attached image depicts the processes of photosynthesis and cellular respiration. Photosynthesis is the process whereby autotrophic organisms use CO2 (carbon dioxide) and H2O (water) in the presence of sunlight to make glucose (C6H12O6). The equation is as follows:

6CO2 + 6H2O + sunlight → C6H12O6 + 6O2

On the contrary is the process of cellular respiration, which involves the breakdown of glucose (sugar) in order to release energy (ATP). The equation is as follows:

C6H12O6 + 6O2 → 6CO2 + 6H2O + energy

According to this question, the option B which says that "Sugar is broken down to release energy" is CORRECT.

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How many molecules of O2 will be required to produce 28.8 g of water?
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For the overall reaction below, which of the following is the correctly written rate law? Overall reaction: O3(g)+2NO2(g)→N2O5(g
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Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

O_3(g)+NO_2(g)\rightarrow NO_3(g)+O_2(g)   slow

NO_3(g)+NO_2(g)\rightarrow N_2O_5(g)   fast

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O_3(g)+2NO_2(g)\rightarrow N_2O_5(g)+O_2(g)

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6 0
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Consider the following unbalanced chemical equation. C5H12(l) + O2(g) → CO2(g) + H2O(l) If 21.9 grams of pentane (C5H12) are bur
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Answer : The mass of water produced will be 32.78 grams.

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Mass of C_5H_{12} = 21.9 g

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First we have to calculate the moles of C_5H_{12}.

\text{Moles of }C_5H_{12}=\frac{\text{Mass of }C_5H_{12}}{\text{Molar mass of }C_5H_{12}}=\frac{21.9g}{72.15g/mole}=0.3035moles

Now we have to calculate the moles of H_2O.

The balanced chemical reaction will be,

C_5H_{12}(l)+8O_2(g)\rightarrow 5CO_2(g)+6H_2O(l)

From the balanced reaction we conclude that

As, 1 mole of C_5H_{12} react to give 6 moles of H_2O

So, 0.3035 moles of C_5H_{12} react to give 0.3035\times 6=1.821 moles of H_2O

Now we have to calculate the mass of H_2O.

\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass of }H_2O

\text{Mass of }H_2O=(1.821mole)\times (18g/mole)=32.78g

Therefore, the mass of water produced will be 32.78 grams.

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