Answer:
1-butanol has higher boiling point mainly due to presence of hydrogen bonding.
Explanation:
Diethyl ether is a polar aprotic molecule due to presence of polar C-O-C moiety. Hence only dipole-dipole intermolecular force exist between diethyl ether molecules.
1-butanol is a polar protic molecule due to presence of C-OH moiety. Therefore dipole-dipole force along with hydrogen bonding exist between 1-butanol molecules.
So, intermolecular force is higher in 1-butanol as compared to diethyl ether. Hence more temperature is required to break intermolecular forces of 1-butanol to boil as compared to diethyl ether.
So, 1-butanol has higher boiling point mainly due to presence of hydrogen bonding.
The answer would be A.Bias because the scientist can form a Bias opinion based on his beliefs
When ΔG° is the change in Gibbs free energy
So according to ΔG° formula:
ΔG° = - R*T*(㏑K)
here when K = [NH3]^2/[N2][H2]^3 = Kc
and Kc = 9
and when T is the temperature in Kelvin = 350 + 273 = 623 K
and R is the universal gas constant = 8.314 1/mol.K
So by substitution in ΔG° formula:
∴ ΔG° = - 8.314 1/ mol.K * 623 K *㏑(9)
= - 4536
Susan should follow PEMDAS,
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction,
So, the first step should be, to solve the equation in the parentheses.
I hope this helps!
A bond is a force of attraction between atoms. They are mainly fthree types of bonds namely; ionic bond, which involves transfer of electrons between a metal and a non metal, covalent bond which occurs between non metal atoms by sharing of electrons, metallic bond which is a bond in the metal structure between metal atoms and the sea of electrons. in this case carbon and hydrogen are non metals hence they will have a covalent bond between their atoms.
