Given that Joseph has 24 cousins, and he has 6 more females than males, the number of females will be obtained as follows;
suppose he had x males, number of females will be x+6.
The total will be:
x+(x+6)=24
x+x+6=24
2x+6=24
2x=24-6
2x=18
x=18/2
x=9
thus the number of male cousins is 9, the number of female cousins will be 9+6=15
We therefore conclude that he has 9 male cousins and 15 female cousins
Answer:
i cant see the photos
Step-by-step explanation:
sorry talaga
Answer:
B, D and also E
Step-by-step explanation:
Answer:
= 20n + 12
Step-by-step explanation:
There is a common difference d between consecutive terms, that is
d = 52 - 32 = 72 - 52 = 92 - 72 = 20
This indicates the sequence is arithmetic with explicit formula
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 32 and d = 20, thus
= 32 + 20(n - 1) = 32 + 20n - 20 = 20n + 12
